Question

Please Help ME!!!!!!!!!!!!!!

Answer 1

Answer:

The empirical formula of this question is :

C.

$C_{5}H_{7}$

Explanation:

The empirical formula is the simplest whole number ratio of elements in the chemical formula of  the molecule.

It is calculated using:

$Empirical\ formula=\frac{Molecular\ formula}{n}$

n = The common factor

The Molecular formula represents the exact composition of the elements in the compound.

For example :

Molecular formula : C4H8O2

Find the common factor n ?

here , 2 is common factor(which is divisible by 4 ,8,2)

$Empirical\ formula=\frac{Molecular\ formula}{2}$

divide each element by 2

$Empirical\ formula=C_{2}H_{4}O_{1}$

generally 1 is not written

C2H4O is the empirical formula

In this question , the molecular formula C40H56

n = common factor = 8(It is divisible by 40 , 56 )

$Empirical\ formula=\frac{Molecular\ formula}{8}$

$Empirical\ formula=C_{5}H_{7}$

So, correct option is C