Answer:
so i never did this befor so i am sorry hope you get the answer
Explanation:
Answer:
The answer to your question is: yield = 56.27%
Explanation:
Data
CH3CH2CH2CH2OH (l) → CH3 CH2CH2CH2Br
18.54 ml 1-butanol 15.65 g of 1-bromobutane
% yield = ?
density = 0.81 g/ml
MM = 74 g 1- butanol
MM = 137 g 1-bromobutane
Process
Calculate mass of 1- butanol
density = mass/volume
mass = density x volume
mass = 0.81 x 18.54
mass = 15.02 g of 1-butanol
Theoretical yield
74 g of 1- butanol ----------------- 137 g of 1-bromobutane
15.02 g of 1- butanol ------------- x
x = (15.02 x 137) / 74
x = 27.81 g of 1-bromobutane
% yield = experimental yield / theoretical yield x 100
% yield = 15.65 / 27.81 x 100
% yield = 56.28
The balanced equation :
<em>2Al₂O₃⇒ 4Al+3O₂</em>
<h3>Further explanation</h3>
Given
Reaction
Al₂O₃⇒ Al+O₂
Required
Balanced equation
Solution
A chemical reaction is said to be balanced if the number of elements involved in the reaction is the same (either the reactants or the products)
The reaction above is said to be unbalanced because the number of elements Al and O in the reactants and products is not the same.
The balancing step
1. Give a coefficient
Al₂O₃⇒ aAl+bO₂
2. Make an equation
Al, left = 2, right = a⇒a=2
O, left = 3, right = 2b⇒2b=3⇒b=3/2
The equation becomes :
Al₂O₃⇒ 2Al+3/2O₂ x2
<em>2Al₂O₃⇒ 4Al+3O₂</em>
Answer:
Atoms of matter are electrically neutral because their nuclei contain the same number of protons as there are electrons surrounding the nuclei. Electric current and charged objects involve the separation of some of the negative charge of neutral atoms.
Answer : The concentration of NaOH is, 0.336 M
Explanation:
To calculate the concentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Thus, the concentration of NaOH is, 0.336 M
