Answer:
A) increasing the pressure
Explanation:
Given the exothermic reaction:
2SO₂(g) + O₂(g) ↔ 2SO₃(g)
the question asks what will make the number of moles of SO₃(g) to increase.
When an equilibrium is disturbed, the system will shift in order to counteract the change (see <em>Le Chatelier's Principle</em>) So <em>when the pressure is increased in a reaction involving gases, the equilibrium will shift trying to decrease the number of moles </em>(because pressure is produced by molecules hitting the container), that is in this case it will shift towards the right side, towards the production of SO₃, thus increasing the number of moles of SO₃.
The number of moles in the right side is 2 and the number of moles in the left side is 3.
They have the same amounts of electrons
<span>37.9968064 ± 0.0000010 g/mol</span>
Option d: copper.
Because copper is an element, not a mixture.
