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skad [1K]
3 years ago
13

Will a 5g piece of platinum sink or float in water

Physics
1 answer:
Dafna11 [192]3 years ago
5 0
A5 g object will sink until it displaces 5g of water. This behavior is independent of each object's size and shape. Water has a density of 1 g/cm3.
You might be interested in
What circumstance would allow an officer to search a home even if they didn’t have a warrant?
Ipatiy [6.2K]

Answer:

A

Explanation:

The officer would have had permission regardless of anything else, kind of like letting someone into your house.

5 0
3 years ago
Which are characteristics of mammals? Check all that apply.
Neporo4naja [7]

Answer:

one of the characteristics of a mammal is their several hollow bones another is their three chambered heart and the last is highly developed nervous system

Explanation:

the reason i picked those three is because not all mammals live their life on land and also mammals font have internal fertillization when they are done they take care of their babies and when they grow up they live their own life

6 0
3 years ago
The motion of an object undergoing constant acceleration can be modeled by the kinematic equations. One such equation is xf=xi+v
Arturiano [62]

Answer:

a = 1.72 m/s²

Explanation:

The given kinematic equation is the 2nd equation of motion. The equation is as follows:

xf = xi + (Vi)(t) + (1/2)(a)t²

where,

xf = the final position =  5000 m

xi = the initial position = 1000 m

Vi = the initial velocity = 15 m/s

t = the time taken = 60 s

a = acceleration = ?

Therefore,

5000 m = 1000 m + (15 m/s)(60 s) + (1/2)(a)(60 s)²

5000 m = 1000 m + 900 m + a(1800 s²)

5000 m = 1900 m + a(1800 s²)

5000 m - 1900 m = a(1800 s²)

a(1800 s²) = 3100 m

a = 3100 m/1800 s²

<u>a = 1.72 m/s²</u>

5 0
3 years ago
If the mass of an object stays the same and you apply more force what will happen to the objects motion
vovikov84 [41]

it will move the object if you apply force, because of that it will stay the same with newton's law.

4 0
3 years ago
A 5.3 kg cat and a 2.5 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw. how far to the left of the pivot must
nika2105 [10]
Moment about the pivot must be equal for the seesaw to balance. Initially, the first cat and the bowl are at 2 m from the pivot.

The moment due to cat = 5.3*2 = 10.6 kg.m
The moment due to bowl = 2.5*2 = 5 kg.m
The unbalanced moment = 10.6 - 5 = 5.6 kg.m

Therefore, the 3.7 kg cat should stand at a distance x from the pivot in left to balance the 5.6 kg.m.
That is,
3.7*x = 5.6 => x = 5.6/3.7 = 1.5134 m to the left (on the side of the bowl)
7 0
3 years ago
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