The resistance of a conductor is given by

where L is the length of the wire,

the resistivity of the material and A the cross-sectional area.
We can see that if all the other quantities do not change, if the new length of the conductor is 4 times the original length:

, then the new resistance is also 4 times the original value:
Answer:
It releases some of the energy into the atmosphere as hot steam.
Explanation:
I assume the block plows into the bank of sand with a velocity of 6 m/s and comes to a stop in 2 s.
Answer:
ugmd = 1/2 kx²
d = (1/2 kx²) / (ugm)
= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)
= 7.4 m
ugmd = 1/2 mv²
v = √2ugd
= √(2(0.23)(9.81 m/s²)(7.4 m)
= 5.8 m/s
Explanation:
Answer:
P=740 KPa
Δ=7.4 mm
Explanation:
Given that
Diameter of plunger,d=30 mm
Diameter of sleeve ,D=32 mm
Length .L=50 mm
E= 5 MPa
n=0.45
As we know that
Lateral strain



We know that




So the axial pressure


P=740 KPa
The movement in the sleeve


Δ=7.4 mm