Answer:
Magnetic force, ![F = 3.52\times 10^{-13}\ N](https://tex.z-dn.net/?f=F%20%3D%203.52%5Ctimes%2010%5E%7B-13%7D%5C%20N)
Explanation:
Given that,
A beryllium-9 ion has a positive charge that is double the charge of a proton, ![q=2\times 1.6\times 10^{-19}\ C=3.2\times 10^{-19}\ C](https://tex.z-dn.net/?f=q%3D2%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5C%20C%3D3.2%5Ctimes%2010%5E%7B-19%7D%5C%20C)
Speed of the ion in the magnetic field, ![v=5\times 10^6\ m/s](https://tex.z-dn.net/?f=v%3D5%5Ctimes%2010%5E6%5C%20m%2Fs)
Its velocity makes an angle of 61° with the direction of the magnetic field at the ion's location.
The magnitude of the field is 0.220 T.
We need to find the magnitude of the magnetic force on the ion. It is given by :
![F=qvB\\\\F=3.2\times 10^{-19}\times 5\times 10^6\times 0.22\\\\F=3.52\times 10^{-13}\ N](https://tex.z-dn.net/?f=F%3DqvB%5C%5C%5C%5CF%3D3.2%5Ctimes%2010%5E%7B-19%7D%5Ctimes%205%5Ctimes%2010%5E6%5Ctimes%200.22%5C%5C%5C%5CF%3D3.52%5Ctimes%2010%5E%7B-13%7D%5C%20N)
So, the magnitude of magnetic force on the ion is
.
Answer:
Study hard , focus on your studies and alyways ask questions .
You cant skip nothing. All the lessons are important! Sorry about you free time :/
Answer:
Explanation:
fringe separation or fringe width is directly proportional to wavelength .
Δ₁ / Δ₂ = wave length of first laser / wavelength of second laser
Δ₁ is fringe separation in first case and Δ₂ is fringe separation in second case.
putting the given values
632.8 / wavelength of second laser = 4.5 / 4.64
wavelength of second laser = 632.8 x (4.64 / 4.5)
= 652.48 nm
652 nm