Answer:
As force = tension in string so tension in string is 400N
Explanation:
Answer:
A. 33.77 m/s
B. 6.20 s
Explanation:
Frame of reference:
Gravity g=-9.8 m/s^2; Initial position (roof) y=0; Final Position street y= -21 m
Initial velocity upwards v= 27 m/s
Part A. Using kinematics expression for velocities and distance:

Part B. Using Kinematics expression for distance, time and initial velocity

Since it is a second order equation for time, we solved it with a calculator. We pick the positive solution.
Work is force times distance. So here we have
W=(5000N)x(3000m)=1.5x10^7J
Or 15MJ (megajoules)
Note: I believe this requires a illustration to be shown.
Answer: Wherever the persons original spot was before he/she walked 15 feet to the left.