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-BARSIC- [3]
3 years ago
8

An electron moving at 2.97×103 m/s in a 1.25 T magnetic field experiences a magnetic force of 1.40×10−16 N . What angle (in degr

ees) does the velocity of the electron make with the magnetic field? There are two possible answers. [Hint: Most calculators will only return the answer that falls in the first quadrant (0 - 90 degrees), but there is another angle in the second quadrant (90 - 180 degrees) that also satisfies the equation.]
Physics
1 answer:
lora16 [44]3 years ago
5 0

To solve the problem it is necessary to take into account the concepts related to the Magnetic Force, which is given by,

F= qvBsin\theta

Where

F= Magnetic force

q= charge of proton

v= velocity

B Magnetic field

\theta=Angle between the velocity and the magnetic field.

Re-arrange the equation to find the angle we have,

\theta = sin^{-1}(\frac{F}{qvB})

Replacing our values we have,

V= 2.97*10^3m/s\\B = 1.25T\\F = 1.4*10^{-16}N\\q = 1.6*10^{-19}C\\

Then,

\theta = sin^{-1}(\frac{1.4*10^{-16}}{(1.6*10^{-19})(1.25)(2.97*10^3)})\\\theta = 13.63\°

The angle between 0 to 180 degrees would be,

\theta' = 180-13.63\\\theta' = 166.36

Therefore the two angles required are 13.63° and 166.36°

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A disk ring of inner radius a and outer radius b lying on the y − z plane has a uniform surface electric charge density +σ(>
solmaris [256]

Answer:

a)  V = k 2π σ (√(b² + x²) - √ (a² + x²)) ,  

b)  E = - k 2π σ x (1 /√(b² + x²) - 1 /√(a² + x²))

Explanation:

a) The expression for the electric potential is

        V = k ∫ dq / r

For this case, consider the disk formed by a series of concentric rings of radius r and width dr, the distance of each ring to point P

         R = √(x² + r²)

The charge on a ring is

        σ = dq / dA

The area of ​​a ring is

        A = π r

        dA = 2π r dr

So the charge is

        dq = σ  2π r dr

We substitute

       V = k σ 2pi ∫ r dr / √(r² + x²)

We integrate

       V = k 2π σ √(r² + x²)

We evaluate from the lower limit r = a to the upper limit r = b

      V = k 2π σ (√(b² + x²) - √ (a² + x²))

 

b) the electric field and the potential are related

        E = - dV / dx

        E = - k 2π σ (1/2 2x /√(b² + x²) - ½ 2x /√(a² + x²))

        E = - k 2π σ x (1 /√(b² + x²) - 1 /√(a² + x²))

7 0
3 years ago
A stone is tied to a 0.85-meter cord. it is swung in a circle at a constant rate of 6.0 m/s. what is the centripetal acceleratio
Andrei [34K]

Answer:42.4m/s^2

Explanation:

Velocity(v)=6m/s

Radius(r)=0.85 meter

Centripetal acceleration=(v x v) ➗ r

Centripetal acceleration=(6 x 6) ➗ 0.85

Centripetal acceleration=36 ➗ 0.85

Centripetal acceleration=42.4

5 0
3 years ago
Guys help me with this question.​
sleet_krkn [62]

Answer:

Explanation:

Brownian motion is a random (irregular) motion of particles e.g smoke particle. The set up in the diagram can be used to observe the motion of smoke.

1. The apparatus used are:

A is a source of light

B is a converging lens

C is a glass smoke cell

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2. The uses of the apparatus are:

A - produces the light required to so as to see clearly the movement of the particles.

B - converges the rays of light from the source to the smoke cell.

C - is made of glass and used for encamping the smoke particles so as not to mix with air.

D - is used for the clear view or observation or study of the motion of the smoke particles in the cell.

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The Andromeda Galaxy (our nearest spiral neighbor) has spectral lines that show a blue shift. From this we may conclude that:
saw5 [17]

The universe is the collection of galaxies, The Andromeda Galaxy has spectral lines with blue shift. The conclusion is that the Universe has stopped expanding.

<h3>What is Andromeda Galaxy?</h3>

The Andromeda Galaxy is the nearest spiral neighbor that has spectral lines showing a blue shift.

Therefore, this concludes that, the Universe has stopped expanding. This galaxy is slowly shifting towards us.

Learn more about Andromeda Galaxy.

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8 0
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What describes the movement of a fluid during convection?
damaskus [11]
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