Pick up truck, if it's got a large mass. kinetic energy is 1/2 mv^2. so in terms of v the truck and cycle would be neck and neck. but truck is presumably more massive.
Mean is the same thing as average, so to find this you would add all of the numbers together and divide them by the amount of numbers you added. For example, (6+9+11)/3
Median is the middle number of the list of numbers, but you have to put them in numerical order first. If there is not an exact middle, you would add the middle two together and divide by two.
Mode is the number that occurs most often within the list of numbers.
Answer:
the angle is about 67.79 degrees
Explanation:
We know that at its maximum height, the vertical component of the projectile's launching (initial) velocity (Vyi) is zero, so at that point it total velocity equals the horizontal component of the initial velocity (Vxi = 0.5 m/s)
We also know that the maximum height of the projectile is given by the square of its initial vertical component of the velocity (Vyi) divided by 2g, therefore half of such distance is :
we can use this information to find the y component of the velocity at that height via the formula:
Now we use the information that tells us the speed of the projectile at this height to be 1 m/s. That should be the result of the vector addition of the vertical and horizontal components:
Now we can use the arc-tangent to calculate the launching angle, since we know the two initial component of the velocity vector:
Answer:
0.333 i1
Explanation:
from figure
iB = i2
i1 = iA
i1 = iA = iB+iC = i2+iC
all resistances are equal o R
i1 = E/[R + 2R||R + R] = E/[8R/3] = 3E/8R
since if v is constant then i is inversely proportional to R
iB/iC = R/2R = 1/2
iC = 2iB = 2i2
and i1 = iB+iC = iB+2iB => i1 = 3iB = 3i2
thus i2 = i1/3
or
the equivalent resistance is
Req = [R || (R+R) ] + ( R + R)
Req = 2R/3 + 2R = 8R/3 ohm
current i1 = E / Req = E / ( 8R/3) = 3E/8R
i1 is divided in two parts as i2 = ib and ic
i1 is divided in i2 and ic in ratio 1 :2
Twice the current will flow through RC as will flow through RB and R2. So the current flowing in R1 and RA is divided by 3,
so i2 is 0.33*i1
i2 = [ 1 / (1+2) ] * i1 = 1/3 * i1
i2 = i1 / 3 = 0.333 i1