Explanation:
It is given that,
Mass of a bungee jumper is 65 kg
The time period of the oscillation is 38 s, hitting a low point eight more times.It means its time period is

After many oscillations, he finally comes to rest 25.0 m below the level of the bridge.
For an oscillating object, the time period is given by :

k = spring stiffness constant
So,

When the cord is in air,
mg=kx
x = the extension in the cord

So, the unstretched length of the bungee cord is equal to 25 m - 5.6 m = 19.4 m
Answer:
16∠45° Ω
Explanation:
Applying,
Z = V/I................... Equation 1
Where Z = Impedance, V = Voltage output, I = current input.
Given: V = 120cos(10t+75°), = 120∠75°, I = 7.5cos(10t+30) = 7.5∠30°
Substitute these values into equation 1
Z = 120cos(10t+75°)/7.5cos(10t+30)
Z = 120∠75°/ 7.5∠30°
Z = 16∠(75°-30)
Z = 16∠45° Ω
Hence the impedance of the linear network is 16∠45° Ω
Voltage=Energy/Charge, V=E/Q
V in volts V, E in joules J, Q in coulombs C.
or
Voltage= Current×Resistance, V=IR
V in volts V, I in amperes A and R in ohms Ω