Answer: 500 s
Explanation:
Speed
is defined as a relation between the distance
and time
:

Where:
is the speed of light in vacuum
is the distance between the Earth and Sun
is the time it takes to the light to travel the distance
Isolating
:


Finally:

Answer:
i) Distancia, ii) La cinta métrica es impracticable.
Explanation:
i) El concepto físico que se construye únicamente del punto de salida y el punto de llegada a la Luna es el concepto de desplazamiento, definido como la distancia en línea recta de un punto en el espacio con respecto a un punto de referencia (la Tierra en este caso).
La distancia puede involucrar trayectorias curvilíneas entre los puntos mencionados.
ii) Por último, el uso de una cinta métrica es impracticable debido a la cantidad de material a utilizar y los efectos gravitacionales, electromagnéticos y mecánicos que inducen a una deflexión o una ruptura de esa cinta debido a la magnitud de la distancia entre las superficies del planeta y el satélite, respectivamente.
En este caso, es mejor utilizar la medición con tecnología láser, basadas en el fenómeno del electromagnetismo.
Helium is lighter than air from the lungs.
Explanation:
A balloon filled with the air from lungs will sink to the ground but a balloon filled with Helium floats because helium is lighter than air.
Air is a mixture of many gases.
The air from the lungs is predominantly made up of carbon dioxide and water vapor.
- Gram per mole of carbon dioxide is 44. Water vapor is 18.
- Compared to helium which is 4, we see that the gas is lighter.
- Since the gas is lighter, it will float in air.
- The main component of air around us is nitrogen gas with a gram per mole of 28.
- A balloon filled with more of air from the lungs weigh more than that will filled air around and even far more than helium gas.
- This will cause a helium filled balloon to float.
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Answer:
The farther star will appear 4 times fainter than the star that is near to the observer.
Explanation:
Since it is given that the luminosity of the 2 stars is same thus they radiate the same energy per unit time
Consider a spherical wave front of energy 'E' that leaves both the stars (Both radiate 'E' as they have same luminosity)
This Energy is spread over the whole surface area of sphere Thus when the wave front is at a distance 'r' the energy per unit surface area is given by

For the star that is twice away from the earth the distance is '2r' thus we will receive an energy given by
Hence we sense it as 4 times fainter than the nearer star.