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3 years ago

10

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1 answer:

Sedaia [141]3 years ago

3 0

This is the definition of a variable.

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Help me with find the slope PLEASEEEE I NEED HELPP

dangina [55]

Answer:

y=-1

x=-3

Step-by-step explanation:

4 0

3 years ago

3-1/8a=1/4<br><br> Pleasseeee help

Vika [28.1K]

3 - 1/8a = 1/4

The goal is to isolate "a" and its coefficient to make the simplification process easier.

Start by subtracting 3 from both sides:

3 - 3 - 1/8a = 1/4 -3

-1/8a = 1/4 - 3

Next, multiply 3 by 4/4 to convert it into a fraction:

-1/8a = 1/4 - [3 • (4/4)]

-1/8a = 1/4 - 12/4

-1/8a = - 11/4

Multiply both sides by -8:

(-8) -1/8a = - 11/4 (-8)

a = 88/4 = 22

Therefore, a = 22.

7 0

3 years ago

Read 2 more answers

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

3 years ago

PLS HELP ME I ONLY HAVE 5 MINUTES PLS

Viefleur [7K]

Answer: 71 ft

i hope its the right answeer, do well

3 0

3 years ago

according to the fundamental theorem of algebra , how many zeros does the polynomial below have x^4 +5x^3+10x^2+20x+24

Vinil7 [7]

Answer:

4

Step-by-step explanation:

the Fundamental Theorem of Algebra states that for any polynomial of degree n, there are n roots, some of which may be complex

The polynomial shown is of degree 4 ( highest exponent of x )

Hence the polynomial has 4 roots/ zeros

8 0

3 years ago

Read 2 more answers