We have the given I = 10^-1 and I₀ = 10^-12.
Simply plugging in the values to the equation, we have:
L = 10log(10^-1/10^-12)
L = 110 Db
The answer is D.
(I used a scientific calculator in solving for L).
Answer:
A' will be located 10 units from point A along ray PA
Step-by-step explanation:
we know that
The scale factor is equal to 3
To obtain PA', multiply PA by the scale factor
so
PA'=PA*3
PA=5 units
substitute
PA'=(5)*3=15 units
AA'=PA'-PA=15-5=10 units
therefore
A' will be located 10 units from point A along ray PA
Answer:
6/5m
or
1 1/5m
Step-by-step explanation:
5 - 3 4/5 = x
5/1 - 19/5 = x
5/1(5/5) - 19/5 = x
25/5 - 19/5 = x
25/5 - 19/5 = 6/5
x = 6/5 or 1 1/5
Log5(x)+log5(4x-1)
As the bases are the same the number doesn't matter
Log (a) + log(b) =log (ab)
Log(4x^2-x)
(x )(4x-1)
x=0.25 or x=0
Log(4×0.25^2-0.25) = log(0) = Infinity
Same with 0. So no answer
X<22
x>-7
x<13
x>5
x>-39
i hope this helps
