Answer:
option (d) is false.
Explanation:
Acid dissociation equilibrium of HCN is represented as-

Acid dissociation constant,
, is represented as-
![K_{a}=\frac{[H^{+}][CN^{-}]}{[HCN]}](https://tex.z-dn.net/?f=K_%7Ba%7D%3D%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5BCN%5E%7B-%7D%5D%7D%7B%5BHCN%5D%7D)
where species inside third bracket represents equilibrium concentrations of respective species
So, evidently, presence of excess
(or NaCN) in solution will combine with
to produce HCN. Hence
will be larger that it would be if only the HCN solution were present.
According to Le-chatlier principle, addition of HCN will shift equilibrium towards right and addition of NaCN will shift equilibrium towards left to keep constant
value at a particular temperature.
NaOH gives acid-base reaction with HCN to produce NaCN and water. So, addition of NaOH will increase concentration of
and decrease concentration of HCN
Red blood cells is correct
Answer:
48.75 g of AgCl
11.60 g of H₂S
Solution:
The Balance Chemical Equation is as follow,
Ag₂S + HCl → AgCl + H₂S
<u>Calculate amount of AgCl produced</u><u>,</u>
According to equation,
247.8 g (1 mol) of Ag₂S produces = 143.32 g (1 mol) of AgCl
So,
84.3 g of Ag₂S will produce = X g of AgCl
Solving for X,
X = (84.3 g × 143.32 g) ÷ 247.8 g
X = 48.75 g of AgCl
<u>Calculate amount of H</u><u>₂</u><u>S produced</u><u>,</u>
According to equation,
247.8 g (1 mol) of Ag₂S produces = 34.1 g (1 mol) of H₂S
So,
84.3 g of Ag₂S will produce = X g of H₂S
Solving for X,
X = (84.3 g × 34.1 g) ÷ 247.8 g
X = 11.60 g of H₂S
Answer:
Explanation:
According to octet rule there should be 8 electrons in the atom's subshell/valence shell. Giving it the same electronic configuration as a noble gas.
among the options:
c) option is correct, as 5 bonds to carbon is violating the octet Rule, 5 bonds means 10 electrons exceeding the noble gas configuration and violets the octet rule.
All the other options are are incorrect, they are following
octet rule. Three bonds of carbon is possible in the case of carbocation.
Answer: The volume of the gold is 
The mass of gold is 19.3 g
The density of gold is 
Explanation:
Density is defined as the mass contained per unit volume.

Given : Mass of gold = 19.3 grams
To calculate the volume of cube, we use the equation:

where,
V = volume of cube
a = edge of cube
Volume of gold = 
Putting values in above equation, we get:
Putting in the values we get:

Thus density of gold will be 