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NNADVOKAT [17]
4 years ago
6

I need help understanding this problem

Chemistry
1 answer:
kotykmax [81]4 years ago
6 0

POPOPOPOPOPOPOPOPOPOPOPOPOPOPO

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For a solution equimolar in HCN and NaCN, which statement is false? a. [H+] is larger than it would be if only the HCN were in s
balandron [24]

Answer:

option  (d) is false.

Explanation:

Acid dissociation equilibrium of HCN is represented as-

 HCN\rightleftharpoons H^{+}+CN^{-}

Acid dissociation constant, K_{a}, is represented as-

K_{a}=\frac{[H^{+}][CN^{-}]}{[HCN]}

where species inside third bracket represents equilibrium concentrations of respective species

So, evidently, presence of excess CN^{-} (or NaCN) in solution will combine with H^{+} to produce HCN. Hence H^{+} will be larger that it would be if only the HCN solution were present.

According to Le-chatlier principle, addition of HCN will shift equilibrium towards right and addition of NaCN will shift equilibrium towards left to keep constant K_{a} value at a particular temperature.

NaOH gives acid-base reaction with HCN to produce NaCN and water. So, addition of NaOH will increase concentration of CN^{-} and decrease concentration of HCN

6 0
3 years ago
Which part of the blood is correctly paired with its function
iogann1982 [59]
Red blood cells is correct
6 0
4 years ago
Calculate the mass of each product formed when 84.3 g of silver sulfide reacts with excess hydrochloric acid: ag2s(s) + hcl(aq)
oee [108]

Answer:

              48.75 g of AgCl

               11.60 g of H₂S

Solution:

The Balance Chemical Equation is as follow,

                                     Ag₂S  +  HCl     →     AgCl  +  H₂S

<u>Calculate amount of AgCl produced</u><u>,</u>

According to equation,

                247.8 g (1 mol) of Ag₂S produces  =  143.32 g (1 mol) of AgCl

So,

                         84.3 g of Ag₂S will produce  =  X g of AgCl

Solving for X,

                      X  =  (84.3 g × 143.32 g) ÷ 247.8 g

                      X  =  48.75 g of AgCl

<u>Calculate amount of H</u><u>₂</u><u>S produced</u><u>,</u>

According to equation,

                247.8 g (1 mol) of Ag₂S produces  =  34.1 g (1 mol) of H₂S

So,

                         84.3 g of Ag₂S will produce  =  X g of H₂S

Solving for X,

                      X  =  (84.3 g × 34.1 g) ÷ 247.8 g

                      X  =  11.60 g of H₂S

6 0
3 years ago
Which situation would violate the octet rule?
jolli1 [7]

Answer:

Explanation:

According to octet rule there should be 8 electrons in the atom's subshell/valence shell. Giving it the same electronic configuration as a noble gas.

among the options:

c) option is correct, as 5 bonds to carbon is violating the octet Rule, 5 bonds means 10 electrons exceeding the noble gas configuration and violets the octet rule.

All the other options are are incorrect, they are following

octet rule. Three bonds of carbon is possible in the case of carbocation.

6 0
3 years ago
Each cubic centimeter of gold has a mass of 19.3 g. A cube of gold measures 4.23 cm on each edge. (a) What is the volume of the
aivan3 [116]

Answer: The volume of the gold is   75.68g/cm^3

The mass of gold is 19.3 g

The density of gold is 0.25g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of gold = 19.3 grams

To calculate the volume of cube, we use the equation:

V=a^3

where,

V = volume of cube

a = edge of cube

Volume of gold = (4.23cm)^3=75.68cm^3

Putting values in above equation, we get:

Putting in the values we get:

Density=\frac{19.3g}{75.68cm^3}=0.25g/cm^3

Thus density of gold will be 0.25g/cm^3

4 0
3 years ago
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