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seraphim [82]
2 years ago
8

Question 5

Chemistry
1 answer:
Kobotan [32]2 years ago
7 0

This hypothesis can be further substantiated by having different concentrations of acid and the same mass of limestone.

<h3>Rate of reaction</h3>

Though the question is incomplete, we must try to answer it the much we can. Recall that a hypothesis is a tentative explanation for an observation which is subject to empirical verification.

We know that the rate of reaction depends on the concentration of the acid. This hypothesis can be further substantiated by having different concentrations of acid and the same mass of limestone.

Learn more about rate of reaction: brainly.com/question/8592296

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bekas [8.4K]

i think the answer is C but don't take my word for it

4 0
3 years ago
10 moles of carbon dioxide has a mass of 440 g. What is the relative formula mass of carbon dioxide?
Ksenya-84 [330]

Answer: 44g

Explanation: The formular for finding Moles is ;

Moles =  Mass / Molar Mass or Formular Mass.

Base on this question; Moles = 10, Mass = 440g, and Formular Mass = ?

Making 'Formular Mass', subject of the formular; we thus have;

Formular mass = Mass / Moles = 440/ 10 = 44g

7 0
3 years ago
Equal masses (in grams) of hydrogen gas and oxygen gas are reacted to form water. Which substance is limiting?
Sonbull [250]

Answer:

a. Oxygen gas is limiting

Explanation:

hydrogen gas and oxygen gas are reacted to form water

2H₂ + O₂  →  2H₂O

the above balanced equation shows that 2 moles of H₂ is required for 1 mole of O₂

Given equal masses of H₂ and O₂

assuming 'x' gm for each, no. of moles of each gas  =

no. of moles of H₂ = x/2 = 0.5x moles

no.of moles of O₂ = x/32 = 0.031x moles

This shows that no. of moles of O₂ is very less so O₂ will become the limiting reagent.

3 0
3 years ago
Read 2 more answers
How much heat is absorbed when 447 g of water , Cp = 4.184 J/goC, goes from 25.0 oC to 35.0 oC?
Digiron [165]

Answer:

The answer to your question is  Q = 18702.5 J

Explanation:

Data

mass of water = m = 447 g

Cp = 4.184 J/g°C

Temperature 1 = T1 = 25°C

Temperature 2 = T2 = 35°C

Heat = Q = ? Joules

Process

1.- Write the formula to calculate heat

    Q = mCp(T2 - T1)

2.- Substitution

    Q = (447)(4.184)(35 - 25)

3.- Simplification

    Q = (447)(4.184)(10)

4.- Result

    Q = 18702.5 J

8 0
3 years ago
PLZ HELP PLZ PLZ ILL MARK AS BRAINLIESTT!!!!
LuckyWell [14K]

Q.1-

Given,

mass - 10grams

volume - 24 cm³

density = mass/volume

density = 10/24

density = 0.416 g/cm³

Q.2-

Given,

mass - 700grams

volume - 1100cm³

density = mass/volume

density = 700/1100

density = 0.6363 g/cm³

5 0
3 years ago
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