Answer:
Diabetes is a group of diseases that affect how your body uses blood sugar (glucose). Glucose is vital to your health because it's an important source of energy for the cells. Cells are everywhere including the blood, bones and muscles. When you have diabetes, you don’t have enough insulin in your blood (an organ in your body called the pancreas makes insulin). Insulin controls the movement of blood sugar into the cells of the body.
Explanation:
Answer:
1. 6.116x1024 Molecules of H2O
2. 13400 L
3. 8.001x1024 Molecules of Mg3(PO4)2
4. 572 g.
5. 1.017x1025 Molecules of N2
6. 7.24 g
.7. 6980 g. of Al(OH)3
8. 3H2 + N2 => 2NH3
9. S8 + 8O2 => 8SO2
10. Ni(ClO3)2→ NiCl2 + 3O2
11. C2H4 + 3O2→ 2CO2 + 2H2O
12. 2KClO3→ 2KCl + 3O2
13. Cu(OH)2 + 2HC2H3O2→ Cu(C2H3O2)2 + 2H2O
14. C3H8 + 5O2→ 3CO2 + 4H2O
15. 191 g of CO
Answer:
Understanding the unit cell of a crystalline solid will help you in determining the empirical formula of the ionic solid compound because they both represent the smallest portion of the whole crystalline solid proportion.
Explanation:
A unit cell is the smallest portion of a crystal lattice, that can show the 3 dimensional pattern of the whole crystal.A formula unit is the lowest whole number ratio of ions in a an ionic compound.By considering the smallest repeating units/ unit cell, you can describe the structure of a crystalline solid.Knowing this can help in determining the empirical formula of the ionic solid compound.
Answer:
The rate law for second order unimolecular irreversible reaction is
![\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%20%3D%20k.t%20%2B%20%5Cfrac%7B1%7D%7B%5BA%5D_%7B0%7D%20%7D)
Explanation:
A second order unimolecular irreversible reaction is
2A → B
Thus the rate of the reaction is
![v = -\frac{1}{2}.\frac{d[A]}{dt} = k.[A]^{2}](https://tex.z-dn.net/?f=v%20%3D%20-%5Cfrac%7B1%7D%7B2%7D.%5Cfrac%7Bd%5BA%5D%7D%7Bdt%7D%20%3D%20k.%5BA%5D%5E%7B2%7D)
rearranging the ecuation
![-\frac{1}{2}.\frac{k}{dt} = \frac{[A]^{2}}{d[A]}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D.%5Cfrac%7Bk%7D%7Bdt%7D%20%3D%20%5Cfrac%7B%5BA%5D%5E%7B2%7D%7D%7Bd%5BA%5D%7D)
Integrating between times 0 to <em>t </em>and between the concentrations of ![[A]_{0}](https://tex.z-dn.net/?f=%5BA%5D_%7B0%7D)
to <em>[A].</em>
![\int\limits^0_t -\frac{1}{2}.\frac{k}{dt} =\int\limits^A_{0} _A\frac{[A]^{2}}{d[A]}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E0_t%20-%5Cfrac%7B1%7D%7B2%7D.%5Cfrac%7Bk%7D%7Bdt%7D%20%3D%5Cint%5Climits%5EA_%7B0%7D%20_A%5Cfrac%7B%5BA%5D%5E%7B2%7D%7D%7Bd%5BA%5D%7D)
Solving the integral
To solve this we use the
equation,
M1V1 = M2V2
where M1 is the concentration of the stock solution, V1 is the
volume of the stock solution, M2 is the concentration of the new solution and
V2 is its volume.
We prepare the solution by measuring 25 mL of the stock solution in a graduated cylinder or by using a pipette. Then, put the stock solution in a 100mL of volumetric flask. Dilute it by adding distilled water up to the 100mL mark in the flask. It should be noted that the lower meniscus of the solution should be the point where you observe the volume.
