Question

The specific heat capacity of copper is 0.09 cal/g°C. How much energy is needed to flow into a 10-gram sample to change its temperature from 20°C to 21°C?

Answer 1

ΔT = 21º C - 20 ºC => 1 º C

Q = m x C x ΔT

Q = 10 x 0.09 x 1

Q = 0.9 Cal

hope this helps!

Answer 2

Answer : The amount energy needed is, 0.9 cal

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = heat required = ?

m = mass of copper = 10 g

c = specific heat of copper = $0.09cal/g^oC$      

$\Delta T=\text{Change in temperature}$  

$T_{final}$ = final temperature = $21^oC$

$T_{initial}$ = initial temperature = $20^oC$

Now put all the given values in the above formula, we get :

$Q=10g\times 0.09cal/g^oC\times (21-20)^oC$

$Q=0.9cal$

Therefore, the amount energy needed is, 0.9 cal