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3 years ago

Please answer right away

Mathematics

1 answer:

Rufina [12.5K]3 years ago

3 0

Answer:

The answer is 295.

Step-by-step explanation:

If you divided each volume by the number of the jelly beans, it is 2.5

Hope it helped you!

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8.5cm squared = ...mm squared?<br><br> Please explain clearly

tekilochka [14]

1 centimeter = 10 milimeters.
Therefore, 8.5 centimeters squared = 85 millimeters squared.

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3 years ago

An appliance salesperson receives a monthly salary of $2,250 plus a commission of 4.5% on all sales compute total pay for a mont

tino4ka555 [31]

Answer:

the total pay for the month for appliance salesperson = $6680.25

Step-by-step explanation:

salesperson receives a monthly salary of $2,250

commission of 4.5% on all sales compute

total pay for a month and when she sold $98,450 worth of appliances

total pay = $2,250 + 4.5% of $98,450

= $2,250 + $4430.25 = $6680.25

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3 years ago

What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti

Marat540 [252]

Answer:

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

Step-by-step explanation:

Given

$x^2 - 5x - 7 = 0$

Required

Solve for x using:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

First, we need to identify a, b and c

The general form of a quadratic equation is:

$ax^2 + bx + c = 0$

So, by comparison with $x^2 - 5x - 7 = 0$

$a = 1$ $b = -5$ $c = -7$

Substitute these values of a, b and c in

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}$

$x = \frac{5 \± \sqrt{25 +28}}{2}$

$x = \frac{5 \± \sqrt{53}}{2}$

Split the expression to two

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

To solve further in decimal form, we have

$x = \frac{5 + 7.28}{2}$ or $x = \frac{5 - 7.28}{2}$

$x = \frac{12.28}{2}$ or $x = \frac{-2.28}{2}$

$x = 6.14$ or $x = -1.14$

4 0

3 years ago

PLZ HELP!!!! WILL MARK BRAINLIEST!!!!

Yuliya22 [10]

Answer:

2 $a^{3} b^{5$

Step-by-step explanation:

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2 years ago

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Write a declaration for a variable channel that can hold tv channel numbers (1 to 900) and a variable hours_recorded that can ho

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Int channel; double hours_ recorded;

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3 years ago