Simplify the expression:
1 answer:
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Here we will use the trial and error method.
- We will try putting different values of x.
Check the picture below.
something worth noticing
so, we're really graphing x+2, with a hole at x = 3, however, when x = 3, we know that f(x) = 5, but but but, when x = 3, x+2 = 5, so we end up with a continuous line all the way, x ∈ ℝ, because the "hole" from the first subfunction, gets closed off by the second subfunction in the piece-wise.
