Answer:
The second wavelength is 482 nm.
Explanation:
Given that,
Wavelength = 630 nm
Distance from central maxim = 0.51 m
Distance from central maxim of another wavelength = 0.39 m
We need to calculate the second wavelength
Using formula of width of fringe
Here, d and D will be same for both wavelengths
= wavelength
= width of fringe
The width of fringe for first wavelength
....(I)
The width of fringe for second wavelength
....(II)
Divided equation (I) by equation (II)
Hence, The second wavelength is 482 nm.
Answer:
Before:
After:
Explanation:
<u>Conservation of Momentum</u>
Two objects of masses m1 and m2 moving at speeds v1o and v2o respectively have a total momentum of
After the collision, they have speeds of v1f and v2f and the total momentum is
Impulse J is defined as
Where F is the average impact force and t is the time it lasted
Also, the impulse is equal to the change of momentum
As the total momentum is conserved:
We can compute the speed of the second object by solving the above equation for v2f
The given data is
a) The impulse will be computed at the very end of the answer
b) Before the collision
c) After collision
Compute the car's speed:
And the car's momentum is
The Impulse J of the system is zero because the total momentum is conserved, i.e. \Delta p=0.
We can compute the impulse for each object
The force can be computed as
The force on the car has the same magnitude and opposite sign
<span>A lubricant such as oil, grease, graphite powder can reduce the friction between two surfaces. Or using metal balls to space them and reduce the contact surface area as used in ball bearings.</span>
Answer:
C
Explanation:
Earth rotates once in about 24 hours with respect to the Sun, but once every 23 hours, 56 minutes, and 4 seconds with respect to other, distant, stars. Earth's rotation is slowing slightly with time; thus, a day was shorter in the past. This is due to the tidal effects the Moon has on Earth's rotation.
There are 10⁹ picoseconds in 1 Ms
1 picosecond= 10¹² s
1 Ms = 10⁻³ s
so the number of picoseconds in one Ms=(10⁻³ s/1 Ms) * (10¹² Ps/ 1 s)=10⁹
Thus there are 10⁹ picoseconds in 1 Ms
