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blsea [12.9K]
3 years ago
9

Sjskskszpd no djdkzsnkakzx d

Physics
1 answer:
Mazyrski [523]3 years ago
4 0

Answer:

jadjsakdjadkjadhfmafkj

Explanation:

:)

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A "gauge 8" jumper cable has a diameter d of 0.326 centimeters. The cable carries a current I of 30.0 amperes. The electric fiel
AveGali [126]

Answer:

0.0979 N/c

Explanation:

Electric field, E is given as a product of resistivity and current density

E=jP where P is resistivity and j is current density

But the current density is given as

j=\frac {I}{A} where I is current and A is area and A=\pi r^{2}

Substituting this into the first equation then E=P\times \frac {I}{\pi r^{2}}

Given diameter of 0.259 cm= 0.00259 m and the radius will be half of it which is 0.001295 m

E=1.72\times 10^{-8}\times \frac {30}{\pi \times 0.001295^{2}}=9.79\times 10^{-2} N/c=0.0979 N/c

4 0
3 years ago
What is the unit of measurement for expressing the intensity of sound
Irina18 [472]
Decibel - the decibel is a relative unit of measurement equal to one 10th of a bel
5 0
3 years ago
A small block of mass m on a horizontal frictionless surface is attached to a horizontal spring that has force constant k. The b
Rashid [163]

Answer:

v_{max} = |d|\cdot \sqrt{\frac{k}{m} }

Explanation:

The maximum speed of the block occurs when spring has no deformation, that is, there is no elastic potential energy, which can be remarked from appropriate application of the Principle of Energy Conservation:

\frac{1}{2}\cdot k \cdot d^{2} = \frac{1}{2}\cdot m \cdot v^{2}

k \cdot d^{2} = m\cdot v^{2}

v_{max} = |d|\cdot \sqrt{\frac{k}{m} }

5 0
3 years ago
A. Calculate the approximate number of atoms in a bacterium. Assume that the average mass of an atom in the bacterium is ten tim
ludmilkaskok [199]

Answer:

a. Approximate umber of atoms = 10¹¹

b. number of atoms = 50 atoms thick

Note: The question is missing some parts. The complete question is as follows; Calculate the approximate number of atoms in a bacterium. Assume that the average mass of an atom in the bacterium is ten times the mass of a hydrogen atom. (Hint: The mass of a hydrogen atom is on the order of 1×10⁻²⁷ kg and the mass of a bacterium is on the order of 1×10⁻¹⁵ kg)

Explanation:

a. Approximate umber of atoms = mass of bacterium / 10 * mass of hydrogen

number of atoms = 10⁻⁵/ 10 × 10⁻²⁷

number of atoms = 10¹¹ atoms

b. The cell membrane is 10-8 m thick while the hydrogen atom has a diameter of 10-10  m.

The number of atoms in the cell membrane = d1 / 2 × d2

where d1 = diameter of cell membrane; d2 = diameter of hydrogen atom

The number of atoms in the cell membrane = 10⁻ / 2 × 10⁻¹⁰ = 50 atoms

7 0
3 years ago
(c)
lys-0071 [83]
The answer is c. Twelve wants pass an obsessive frequency of the internet
7 0
3 years ago
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