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Veronika [31]
3 years ago
6

How many liters of 15 acid and 33 acid should be mixed to make 40 liters of 21 acid solution answer key?

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
6 0
Answer is: 26.67 liters of 15% acid and 13.33 liters of 33% acid are needed.
ω₁(acid) = 15% = 0,15.
ω₂(acid) = 33% = 0,33.
V₁(acid) = ?
V₂(acid) = ?
V₃(acid) = 40l.
ω₃(acid) = 21% = 0,21
1) V₁ + V₂ = 40l, V₁ = 40 - V₂.
2) 0,15·V₁ + 0,33·V₂ ÷ 40 = 0,21
0,15·(40 - V₂) + 0,33·V₂ ÷ 40 = 0,21
6 - 0,15V₂ + 0,33V₂ ÷ 40 = 0,21.
0,18V₂ = 2,4, V₂ = 13,33l.
V₁ = 40 - 13,33 = 26,67l.
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Percent yield: 78.2%

Explanation:

Based on the reaction:

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<em>4 moles of Al produce 2 moles of Al₂O₃</em>

<em />

To find percent yield we need to find theoretical yield (Assuming a yield of 100%) and using:

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4.6g Al × (1mol / 26.98g) = 0.1705 moles of Al.

As 4 moles of Al produce 2 moles of Al₂O₃, theoretical moles of Al₂O₃ obtained from 0.1705 moles of Al are:

0.17505 moles Al × (2 moles Al₂O₃ / 4 moles Al) = <em>0.0852 moles of Al₂O₃</em>,

In grams (Molar mass Al₂O₃ = 101.96g/mol):

0.0852 moles of Al₂O₃ × (101.96g / mol) =

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3 years ago
What is the percentage strength (w/w) of a solution made by dissolving 62.5 g of potassium chloride in 187.5 ml of water?
kiruha [24]

Percent strength (% w/w) of a solution is defined as the amount of solute present in 100 g of the solution.

Given data:

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The percentage strength = 33.33 %

8 0
3 years ago
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