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QveST [7]
2 years ago
14

More ATP per carbon is produced from oxidation of fatty acids as compared to glucose. However, fatty acids are used primarily to

provide fuel for ATP synthesis during long periods of exercise. Why can't fatty acids be used to fuel short, intense periods of exercise?
A. Short, intense periods of exercise preferentially activate ATP synthesis from glucose.
B. Short, intense periods of exercise do not signal release of fatty acids from adipose tissue.
C. Short, intense periods of exercise do not require ATP synthesis.
D. Short, intense periods of exercise do not provide sufficient time for oxidative phosphorylation to occur.
Chemistry
1 answer:
Luda [366]2 years ago
8 0

Answer:

The correct option is D

Explanation:

Although, option A appears correct but the reason for option A is actually option D. What this means is that, during short intense exercise (anaerobic exercise), the body preferentially activates ATP synthesis from glucose (glycolysis) even though the beta oxidation of fatty acid produces more energy (ATP) - this is because <u>glycolysis occurs many times faster (about a 100 times faster) than the beta oxidation of fatty acid/oxidative phosphorylation</u>. Thus, it can be said that short, intense periods of exercise do not provide sufficient time for oxidative phosphorylation to occur.

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Lady bird [3.3K]
<h2>Answer:</h2><h3>Part 1:</h3>

Location the element zinc (Zn) on the periodic table:

  •    Group number : 12
  •     Period number : 4
  •     Block :  d block
  •      Element : Transition elements.
<h3>Part 2:</h3>

Protons in an atom of Zn:  30

<h3>Part 3:</h3>

Electrons in a Zn atom: 30

<h3>Part 4 :</h3>

Neutron in an atom of Zn: 35


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4 0
3 years ago
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according to the balanced chemical equation below,how many grams of h20 are produced if 3.98g of co2 were produced. 2C18H18 + 25
telo118 [61]

Answer:

Primero debes usar los gramos de co2 y luego buscar su peso molecular, luego de eso usar la relación de moles entre CO2 y H2O y por último buscar el pm del H2O pata ver cuantos gramos de produce.

Explanation:

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3 years ago
An exhaled air bubble underwater at 290.
Vinil7 [7]

The answer for the following problem is mentioned below.

  • <u><em>Therefore the final volume of the gas is 52.7 ml.</em></u>

Explanation:

Given:

Initial pressure (P_{1}) = 290 kPa

Final pressure (P_{2}) = 104 kPa

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To find:

Final volume (V_{2})

We know;

From the ideal gas equation;

    P × V = n × R × T

where;

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V represents the volume of gas

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R represents the universal gas constant

T represents the temperature of the gas

So;

   P × V = constant

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From the above equation;

              \frac{P_{1} }{P_{2} }  = \frac{V_{2} }{V_{1} }

P_{1} represents the initial pressure of the gas

P_{2} represents the final pressure of the gas

V_{1} represents the initial volume of the gas

V_{2} represents the final volume of the gas

Substituting the values of the above equation;

                    \frac{290}{104} = \frac{V_{2} }{18.9}

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<u><em>Therefore the final volume of the gas is 52.7 ml.</em></u>

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Answer:

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hope this helps :)

8 0
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