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QveST [7]
3 years ago
14

More ATP per carbon is produced from oxidation of fatty acids as compared to glucose. However, fatty acids are used primarily to

provide fuel for ATP synthesis during long periods of exercise. Why can't fatty acids be used to fuel short, intense periods of exercise?
A. Short, intense periods of exercise preferentially activate ATP synthesis from glucose.
B. Short, intense periods of exercise do not signal release of fatty acids from adipose tissue.
C. Short, intense periods of exercise do not require ATP synthesis.
D. Short, intense periods of exercise do not provide sufficient time for oxidative phosphorylation to occur.
Chemistry
1 answer:
Luda [366]3 years ago
8 0

Answer:

The correct option is D

Explanation:

Although, option A appears correct but the reason for option A is actually option D. What this means is that, during short intense exercise (anaerobic exercise), the body preferentially activates ATP synthesis from glucose (glycolysis) even though the beta oxidation of fatty acid produces more energy (ATP) - this is because <u>glycolysis occurs many times faster (about a 100 times faster) than the beta oxidation of fatty acid/oxidative phosphorylation</u>. Thus, it can be said that short, intense periods of exercise do not provide sufficient time for oxidative phosphorylation to occur.

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7 0
3 years ago
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By weight atmospheric air is approximately 23.15% oxygen and 76.85% nitrogen. What is the partial pressure of oxygen in the air
inna [77]

Answer:

Partial pressure of oxygen = 23.38 kpa (Approx)

Explanation:

Given:

Amount of oxygen = 23.15%

Amount of nitrogen = 76.85%

Pressure (missing) = 101 kpa

Find:

Partial pressure of oxygen

Computation:

Partial pressure of oxygen = [Amount of oxygen x Pressure]/100

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Partial pressure of oxygen = 23.38 kpa (Approx)

5 0
3 years ago
15-9+6+3 =? What's the answer of this? ​
julia-pushkina [17]
15-9+6+3=

ANSWER

15
6 0
3 years ago
Which material is a material is mixture
Sav [38]

Answer:

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Explanation:

7 0
4 years ago
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What is the hydroxide [OH-] concentration of a solution that has a pOH of 4.90? 14 14 1.26 x10-5 1.26 x10, -5 9.1 9.1 7.94 x 104
polet [3.4K]

Answer:

The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.

Explanation:

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.

POH indicates the concentration of hydroxyl ions [OH-] present in a solution and is defined as the negative logarithm of the activity of hydroxide ions (that is, the concentration of OH- ions):

pOH= -log [OH-]

A solution has a pOH of 4.90. Replacing in the definition of pOH:

4.90= -log [OH-]

Solving:

-4.90= log [OH-]

1.26*10⁻⁵ M= [OH-]

<u><em>The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.</em></u>

3 0
3 years ago
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