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mote1985 [20]
3 years ago
8

A car is traveling at 19m/s. It slows to a stop at a constant rate over 4.2 seconds. How far did the car travel during the 4.2se

conds it took to stop?
Physics
1 answer:
svetlana [45]3 years ago
5 0

The distance covered by the car is 39.9 m

Explanation:

Since the car is slowing at constant rate, it means that its acceleration is constant, therefore we can solve the problem by using the following suvat equation:

s=(\frac{u+v}{2})t

where

s is the distance covered

u is the initial  velocity

v is the final velocity

t is the time elapsed

For the car in this problem, we have

u = 19 m/s (initial velocity)

v = 0 (final velocity)

t = 4.2 s (time elapsed)

Therefore, the distance covered is

s=(\frac{19+0}{2})(4.2)=39.9 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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