A car is traveling at 19m/s. It slows to a stop at a constant rate over 4.2 seconds. How far did the car travel during the 4.2se
1 answer:
The distance covered by the car is 39.9 m
Explanation:
Since the car is slowing at constant rate, it means that its acceleration is constant, therefore we can solve the problem by using the following suvat equation:
where
s is the distance covered
u is the initial velocity
v is the final velocity
t is the time elapsed
For the car in this problem, we have
u = 19 m/s (initial velocity)
v = 0 (final velocity)
t = 4.2 s (time elapsed)
Therefore, the distance covered is
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Answer:
The sound level will be 1.870 dB louder.
Explanation:
Given that,
Power = 130 W
Power = 200 W
We need to calculate the sound level
Using formula of sound level
For one amplifier,
...(I)
For other amplifier,
...(II)
For difference in dB levels
Hence, The sound level will be 1.870 dB louder.