A car is traveling at 19m/s. It slows to a stop at a constant rate over 4.2 seconds. How far did the car travel during the 4.2se
1 answer:
The distance covered by the car is 39.9 m
Explanation:
Since the car is slowing at constant rate, it means that its acceleration is constant, therefore we can solve the problem by using the following suvat equation:
where
s is the distance covered
u is the initial velocity
v is the final velocity
t is the time elapsed
For the car in this problem, we have
u = 19 m/s (initial velocity)
v = 0 (final velocity)
t = 4.2 s (time elapsed)
Therefore, the distance covered is
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where
is the component of the force along the direction of displacement.
As per the question the power P is given as -
Hence alternative definition of power P = F.V