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Ostrovityanka [42]
2 years ago
14

When something is hit harder how does the transverse wave change?

Physics
1 answer:
Flura [38]2 years ago
5 0
When something is hit harder just like when sound is turned up the waves become higher and more frequent like a zig zag more so then wavy.
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Which statement describes Redi’s experiment, which helped disprove spontaneous generation?
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He examined covered and uncovered meat to determine that maggots came from eggs.

In other other words A

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What is the force required to lift the balloon with
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Since the balloon's density is less than the density of the air around it, it's lighter than the air it displaces, there is a net upward buoyant force acting on it, and it floats up !

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Unlike fossil fuels, biomass fuels _____.
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4. Compare how thermal and electrical energy transfer between objects and give an example of how you can
Leokris [45]

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4) we take a can of cold soda there is a transfer from hand to can.  a current passes through a light bulb, it becomes incandescent and gives ligh

5) the law of energy conservation states that energy is neither created nor destroyed, therefore what happens is that you use energy and transform it into another type of energy,

Explanation:

4) This exercise is asked to give some examples of thermal and electrical energy transfer

the transfer of thermal energy occurs when we grasp a hot or cold body due to the difference in temperature between the body and us there is an exchange of heat, for example when drinking a cup of hot coffee there is a transfer of energy from the cup to the hand .

If we take a can of cold soda there is a transfer from hand to can.

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In all modern electrical appliances there is transformation of electrical energy

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3 years ago
A car moving with an initial speed v collides with a second stationary car that is one-half as massive. After the collision the
Mashutka [201]

Answer:

4v/3

Explanation:

Assume elastic collision by the law of momentum conservation:

m_1v = m_1v_1 + m_2v_2

where v is the original speed of car 1, v1 is the final speed of car 1 and v2 is final speed of car 2. m1 and m2 are masses of car 1 and car 2, respectively

Substitute m_2 = m_1/2 \& v_1 = v/3

m_1v = \frac{m_1v}{3} + \frac{m_1v_2}{2}

Divide both side by m_1, then multiply by 6 we have

6v = 2v + 3v_2

3v_2 = 4v

v_2 = \frac{4v}{3}

So the final speed of the second car is 4/3 of the first car original speed

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