Answer:
D. Graphing the force as a function of distance and calculating the area under the curve.
Explanation:
The electric field at the surface of the cylinder is 51428V/m
Given data:
• The length of the charge is l= 7m.
• The charge is q = 2μC..
• The radius the cylinder is r = 10 cm
Since the filament length is so large as compared to the cylinder length that the infinite line of charge can be assumed.
The expression to calculate the electric field is given as,
E=2kλ/r
Here, λ is the linear charge density.
Substitute the values in the above equation,
E = (2×9×109N⋅m^2/C^2×2×10^−6C)/0.1m×7m
E = 51428N/C×(V/m)/(N/C)
=51428V/m
An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. Matter is positively charged if it contains more protons than electrons, and negatively charged if it contains more electrons than protons.
Learn more about charge here:
brainly.com/question/19886264
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In your question where as a golf ball is struck at a ground level and the speed of the ball as a function of time is in the figure where time t=0 and va = 16m/s and vb=32m/s. The following is the answer:
a) How far does the golf ball travel horizontally before returning to ground level?
-<span>80m</span>
<span>(b) What is the maximum height above ground level attained by the ball?
</span>-39.87m
I don't understand this question
Answer:
313.6 m
Explanation:
From the question given above, the following data were obtained:
Time (t) = 8 s
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) =?
The height at which the package was dropped can be obtained as follow:
h = ½gt²
h = ½ × 9.8 × 8²
h = 4.9 × 64
h = 313.6 m
Thus, the package was at a height of 313.6 m when it was dropped.