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3 years ago

Explain different types of thermometer and their thermometry substance

Physics

1 answer:

Rudiy273 years ago

3 0

Answer:

Explained below

Explanation:

1) Liquid in glass thermometer: This type of thermometer is used primarily to measure the temperatures from inspection of changes in volume of liquid.

Thermometry substance is mercury or alcohol

2) Gas thermometer: This type is used to measure temperature as a result of changes in gas pressure or volume.

Thermometry substance is Gas.

3) Resistance thermometer: This type is used to measure temperature due to changes in electric resistance.

Thermometry substance is Resistance wire.

4) Thermocouple thermometer: This type is used to measure the temperature due to changes in electrical potential difference occurring between two metal junctions.

Thermometry substance is two wires that are dissimilar.

5) Bimetallic thermometer: This is a type of thermometer that measures temperature by converting temperature into mechanical displacement by making use of Bimetallic strip.

Thermometry substance is two metals that are dissimilar.

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A vertical piston-cylinder device initially contains 0.1 m^3 of air at 400 K and 100 kPa. At this initial condition, the piston

jenyasd209 [6]

Answer:

$Q=-38.15kJ$

Explanation:

From the question we are told that

Piston-cylinder initial Volume of air $v_1=0.1 m^3$

Piston-cylinder initial temperature $T_1=400k$

Piston-cylinder initial pressure $P_1= 100kpa$

Supply line temperature $T_s=400k$

Supply line pressure $P_s= 500kpa$

Valve final pressure $P_v=500kpa$

Piston movement pressure $P_m=200kpa$

Piston-cylinder final Volume of air $v_2=0.2 m^3$

Piston-cylinder final temperature $T_2=440k$

Piston-cylinder final pressure $P_2= 500kpa$

Generally the equation for conservation of mass is mathematically given by

$Q=m_2 \mu_2-m_1 \mu_1 +W-(m_2-m_1)h$

where

Initial moment

$m_1=\frac{p_1 V_1}{RT_1}$

$m_1=\frac{100*0.1}{0.287*400}$

$m_1=8.7*10^-^2kg$

Final moment

$m_2=\frac{p_2 V_2}{RT_2}$

$m_1=\frac{500*0.3}{0.287*440}$

$m_1=79*10^{-2}kg$

Work done by Piston movement pressure

$W=Pd$

$W=P(v_2-v_1)$

$W=200(0.2-0.1))$

$W=20000J$

Heat function

$h=cT_1$

$h=1.005(400)$

$h=402$

Therefore

$Q=(0.792*0.718(440)-0.0871*0.718(400)+20-(0.792-0.087)*402))$

$Q=-38.15kJ$

It is given mathematically that the system lost or dissipated Heat of

$Q=-38.15kJ$

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3 years ago

the speed of a tortoise and a hare are 1m/s and 3m/s. the mass of hare is 5kg and the tortoise is 20kg. which has greater moment

Novosadov [1.4K]

Answer: tortoise

Explanation:

Given the following :

Speed of tortoise = 1m/s

Speed of hare = 3m/s

Mass of hare = 5kg

Mass of tortoise = 20kg

Momentum = product of Mass and velocity

Momentum of hare = mass of hare × Velocity of hare

Momentum of hare = 5kg × 3m/s = 15kgm/s

Momentum of tortoise = mass of tortoise × Velocity of tortoise

Momentum of tortoise = 20kg × 1m/s = 20kgm/s

Therefore, tortoise has a greater momentum than hare.

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4 years ago

A helicopter is ascending vertically with a speed of 5.10m/s. At a height of 105 m above the Earth, a package is dropped from a

Oksi-84 [34.3K]

Answer:

The time taken for the package to reach the ground is 20.6s

Explanation:

Given that the formula of distance is D = S×T where S represents soeed and T is time. So you have to substitute the following values into the formula :

$distance = speed \times time$