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pav-90 [236]
3 years ago
8

Below are two of the seven original Axioms of URT.

Physics
1 answer:
Fynjy0 [20]3 years ago
6 0

Answer: there is a negative relationship between the reciprocity and the verbal comunication.

Explanation:

The axioms are:

Axiom 1: There is a negative relationship between Uncertainty and Verbal Communication

This means that if we increase the verbal communication, we reduce uncertainty.

We could express this relation as U = -k*Vc

where k is a constant that says for a given change in verbal communication, how big is the change in the uncertainty.

Axiom 5: There is a positive relationship between Uncertainty and Reciprocity

This means that if we increase the reciprocity, we also increase the uncertainty.

We can write this as U = c*R

c is similar to k for the previous axiom.

We can say that U = c*R = -k*Vc

R = -(k/c)*Vc

This means that there is a negative relationship between reciprocity and the verbal communication.

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The resistance of a given conductor depends on its electrical resistivity (\rho), its length(L) and its cross-sectional area (A), as follows:

R=\frac{\rho L}{A}

In this case, we have L'=138L, \rho'=\rho and A'=A. So, the total resistance of the wire with length of 138m is:

R'=\frac{\rho' L'}{A'}\\R'=\frac{\rho 138L}{A}\\R'=138\frac{\rho L}{A}\\R'=138R\\R'=138(0.24\Omega)\\R'=33.12\Omega

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The density of a block of wood is 694 kg/m3. Its mass is 689 g. We tie the block to the bottom of a swimming pool using a single
Serhud [2]

Answer:

<em>The tension in the string = 2.065 N</em>

Explanation:

From Archimedes principle,

R.d = density of the wood block/density of water = weight of the wood block/Upthrust of the wood block in water.

R.d = D₁/D₂ = W/U

W/U =D₁/D₂.................................. Equation 1

Where W = weight of the wood block, U = upthrust of the wood block in water, D₁ = Density of the wood block, D₂ = Density of water.

Making U the subject of the equation,

U = WD₂/D₁........................... Equation 2

Given: W =  mg = (689/1000)9.8 = 6.75 N,  D₁ = 694 kg/m³, D₂ = 1000 kg/m³.

Substituting these values into equation 2,

U = 6.75(694)/1000

U = 4684.5/1000

U = 4.685 N.

Note: Three forces act on the wood block in the pool. and they are

(i) The weight(W) acting downs

(ii) The upthrust (U) acting upwards,

(iii) The Tension (T) in the string, acting upwards.

Thus,

W = U+T

T = W - U ................................. Equation 3

Where W = 6.75 N, U = 4.685 N

T = 6.75 - 4.685

T = 2.065 N.

T = 2.065 N

<em>Thus the tension in the string = 2.065 N</em>

7 0
3 years ago
an object is placed 15.8 cm in front of a thin converging lens with an unknown focal length. if a real image forms behind the le
storchak [24]
<span>On what:

f (is the focal length of the lens) = ? 
p (is the distance from the object to the lens) =15.8 cm
p' (is the distance from the image to the spherical lens) = 4.2 cm

</span><span>Using the Gaussian equation, to know where the object is situated (distance from the point).
</span>
\frac{1}{f} = \frac{1}{p} + \frac{1}{p'}
\frac{1}{f} = \frac{1}{15.8} + \frac{1}{4.2}
\frac{1}{f} = \frac{2.1}{33.18} + \frac{7.9}{33.18}
\frac{1}{f} =  \frac{10}{33.18}
Product of extremes equals product of means:
10*f = 1*33.18
10f = 33.18
f =  \frac{33.18}{10}
\boxed{\boxed{f = 3.318\:cm}}\end{array}}\qquad\quad\checkmark

6 0
4 years ago
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