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tatiyna
3 years ago
9

Select the correct text in the passage.

Physics
2 answers:
kompoz [17]3 years ago
7 0

Answer:

However, occasionally, the planet will seem to reverse direction, and for a short time appears to move from east to west.

serious [3.7K]3 years ago
4 0

Answer:

I have no clue

Explanation:

i just have no clue

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Which type of energy increases when an object’s atoms move faster? A.nuclear B.mechanical C.chemical D.thermal
erica [24]
When an object's atoms move faster, its thermal energy increases and the object becomes warmer.
4 0
3 years ago
Read 2 more answers
True or False: If the initial speed of an object is zero, then the initial position of the object must be the origin. Explain
lions [1.4K]

Answer:

False

Explanation:

It is not necessary, that when the initial speed of the object is zero then it must be at origin.

It may be the object starts motion from the left of origin.

4 0
2 years ago
The copper wire to the motor is 6.0 mm in diameter and 1.1 m long. How far doesan individual electron travel along the wire whil
lesya [120]

Answer:

0.306mm

Explanation:

The radius of the conductor is 3mm, or 0.003m

The area of the conductor is:

A = π*r^2 = π*(.003)^2 = 2.8*10^-5 m^2

The current density is:

J = 130/2.8*10^-5 = 4.64*10^6 A/m

According to the listed reference:

Vd = J/(n*e) = 4.64*10^6 / ( 8.46*10^28 * 1.6*10^-19 ) = 0.34*10^-6 m/s = 0.34mm/s

The distance traveled is:

x = v*t = 0.34 * .90 = 0.306 mm

5 0
3 years ago
Calculate the density of water in kg/m3. Express your answer in kilograms per cubic meter using three significant figures.
Svet_ta [14]

Answer:

This question appear incomplete

Explanation:

This question appear incomplete. However, the density of water is generally known to be 997 kg/m³. The formula used to determine density is mass ÷ volume. In the case of the density of water, the mass is measured in kilograms (kg) while the volume is measured in cubic meter (m³).

8 0
2 years ago
PHYSICS, HELP PLZ??!! 100PTS
romanna [79]

Hi there!

We can begin by calculating the time the ball takes to reach the highest point of its trajectory, which can be found using the following:

t_{max} = \frac{vsin\theta}{g}

Where:

tmax = (? sec)

vsinθ = vertical comp. of velocity = 10sin(48) = 7.43 m/s)

g = acceleration due to gravity (9.8 m/s²)

We can solve for this time:

t_{max} = \frac{7.43}{9.8} = 0.758 s

When the ball is at the TOP of its trajectory, its VERTICAL velocity is equivalent to 0 m/s. Thus, we can consider this a free-fall situation.

We must begin by solving for the maximum height reached by the ball using the equation:

d = y_0 + v_{0y}t + \frac{1}{2}at^2

d = displacement (m)

vi = initial velocity (7.43 m/s)

a = acceleration due to gravity

d = displacement (m)

y0 = initial VERTICAL displacement (28m)

Plug in the values:

d = 28 + 7.43(0.758) + \frac{1}{2}(-9.8)(0.758^2) = 30.817 m

Now, we can use the rearranged kinematic equation:

t = \sqrt{\frac{2h}{g}}

t = \sqrt{\frac{2(30.817)}{9.8}} = 2.51 s

Add the two times together:

0.758 + 2.51 = \boxed{3.266 s}

7 0
2 years ago
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