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kvv77 [185]
3 years ago
14

Why do some combinations of ionic compounds form a precipitate while others do not

Chemistry
2 answers:
olasank [31]3 years ago
5 0

Answer:

This is because of the solubility of the reacting metal salts.

Explanation:

The use of solubility of salts influences the formation of precipitates. Most precipitation reactions occur as a result of the replacement reactions or double placement reactions. A double replacement reaction occurs when two ionic reactants dissociate and bond with respective anion and cation of the other reactant. This is simply a switch over reaction.

A double replacement reaction occurs when a chemical reaction occurs and one of the products formed is insoluble.

Here is an example:

PdSO_{(aq)} + K_{2}S_{(aq)}   = PdS_{(s)} +K_{2}SO_{4}_{(aq)}

Both reactants are acqeous and the product is solid.

Marizza181 [45]3 years ago
4 0

Whether or not such a reaction occurs can be determined by using the solubility rules for common ionic solids.

tell me if i'm wrong

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Explanation:

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3 years ago
Gold is alloyed with other metals to increase its hardness in making jewelery.a) Consider a piece of gold jewelry the weighs 9.8
irinina [24]

Answer:

A). Percentage of gold by mass of the jewellery =

(6.059÷9.85) × 100 = 61.5%

B). Purity of the gold = 0.615 × 24 = 14.76 karat ~ 15 karat gold

Explanation:

Mass of jewellery = 9.85g Volume of jewellery = 0.675cm^3.

Density of gold = 19.3g/cm^3 and density of silver = 10.5g/cm^3

Let the volume of gold in the jewellery be X and the volume of silver in the jewellery be Y

Hence we have

Density = mass/volume or mass = volume × density = for gold = X × 19.3g/cm^3 and for the silver = Y × 10.5g/cm^3

19.3X +10.5Y = 9.85g

Also volume of jewellery is given by

Volume of silver in the jewellery + volume of gold in the jewellery = 0.675cm^3.

X + Y = 0.675cm^3.

Solving the above equations we have

Y = 0.675 - X

Which gives

19.3X + 10.5Y = 9.85g

19.3X + 10.5 × (0.675 - X) =9.85g

19.3X + 7.0875 - 10.5X = 9.85

8.8X + 7.0875 = 9.85

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or X = 0.3139 cm^3

But Y = 0.675 - X

Hence Y = 0.675 - 0.3139 = 0.3611 cm^3

Mass of gold in the jewellery = volume of gold × Density of gold = 0.3139 × 19.3 = 6.059 g

Also mass of silver = 10.5 × 0.3611 = 3.7913g

A). Percentage of gold by mass of the jewellery =

(6.059÷9.85) × 100 = 61.5%

B). Purity of the gold = 0.615 × 24 = 14.76 karat ~ 15 karat gold

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