Answer:
1.99 x 10²³ formula units
Explanation:
Given parameters:
Mass of AgF = 42.15g
Unknown:
The amount of formula units
Solution:
To solve this problem, we set out by find the number of moles in this compound from the given mass.
Number of moles =
molar mass of AgF = 107.9 + 19 = 126.9g/mol
Number of moles = = 0.33 moles
1 mole of a substance = 6.02 x 10²³ formula units
0.33 moles of AgF = 0.33 x 6.02 x 10²³ = 1.99 x 10²³ formula units
Answer:
Explanation:
Calcium is the element of the group 2 and period 4 which means that the valence electronic configuration is .
Chlorine is the element of the group 17 and period 3 which means that the valence electronic configuration is .
Thus, calcium losses 2 electrons to 2 atoms of chlorine and these 2 atoms of chlorine accepts each electron to form ionic bond. This is done in order that the octet of the atoms are complete and they become stable.
Ca Cl
2 1
Cross multiplying the valency, We get,
Thus, the formula of calcium chloride is .