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mrs_skeptik [129]
3 years ago
8

When calculating percent error, the accepted value is in the denominator True or false

Chemistry
2 answers:
kaheart [24]3 years ago
8 0

Answer:

True

Explanation:

AVprozaik [17]3 years ago
6 0
The answer is TRUE

Have a nice day / night! :)
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A student is working on an assignment exploring the characteristics and uses of titanium. He notes in his assignment that it is
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Answer:

Acknowledge the source of relative weight of titanium.

Explanation:

Titanium is a chemical element which durable form of metal. Titanium is 45% lighter than steel. Titanium is made by combination of multiple elements. Titanium is very difficult to extract and this is the reason this element is considered expensive. The students examining the titanium must record the weight of titanium before exploring the characteristics and properties.

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3 years ago
Plz help! NO FAKE ANSWERS PLEASE
aleksklad [387]

Answer:

postion emmsion

Alpha decaya

gamma decay

beta decay

in order

Explanation:

and there is 100% of humans dieing becasue of atoms decays which is sad and also answers the question does life have meeain and no we are all going to die anyways

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2 years ago
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How many moles of oxygen gas, o2, are in a storage tank with a volume of 1.000×105 l at stp?
Mumz [18]
STP means standard temperature and pressure which is equivalent to 273 K and 1 atm, respectively. Assuming ideal gas behavior, the solution for this problem is as follows:

PV = nRT
Solve for n,
n = RT/PV
n = (0.0821 L-atm/mol-K)(273 K)/(1 atm)(1×10⁵ L)
<em>n = 2.24×10⁻⁴ moles</em>
6 0
3 years ago
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Consider the reaction. 2 HBr(g) ¡ H2(g) + Br2(g) a. Express the rate of the reaction in terms of the change in concentration of
Studentka2010 [4]

Answer :

(A) The rate expression will be:

Rate=-\frac{1}{2}\frac{d[HBr]}{dt}=+\frac{d[H_2]}{dt}=+\frac{d[Br_2]}{dt}

(B) The average rate of the reaction during this time interval is, 0.00176 M/s

(C) The amount of Br₂ (in moles) formed is, 0.0396 mol

Explanation :

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The given rate of reaction is,

2HBr(g)\rightarrow H_2(g)+Br_2(g)

The expression for rate of reaction :

\text{Rate of disappearance of }HBr=-\frac{1}{2}\frac{d[HBr]}{dt}

\text{Rate of disappearance of }H_2=+\frac{d[H_2]}{dt}

\text{Rate of formation of }Br_2=+\frac{d[Br_2]}{dt}

<u>Part A:</u>

The rate expression will be:

Rate=-\frac{1}{2}\frac{d[HBr]}{dt}=+\frac{d[H_2]}{dt}=+\frac{d[Br_2]}{dt}

<u>Part B:</u>

\text{Average rate}=-\frac{1}{2}\frac{d[HBr]}{dt}

\text{Average rate}=-\frac{1}{2}\frac{(0.512-0.600)M}{(25.0-0.0)s}

\text{Average rate}=0.00176M/s

The average rate of the reaction during this time interval is, 0.00176 M/s

<u>Part C:</u>

As we are given that the volume of the reaction vessel is 1.50 L.

\frac{d[Br_2]}{dt}=0.00176M/s

\frac{d[Br_2]}{15.0s}=0.00176M/s

[Br_2]=0.00176M/s\times 15.0s

[Br_2]=0.0264M

Now we have to determine the amount of Br₂ (in moles).

\text{Moles of }Br_2=\text{Concentration of }Br_2\times \text{Volume of solution}

\text{Moles of }Br_2=0.0264M\times 1.50L

\text{Moles of }Br_2=0.0396mol

The amount of Br₂ (in moles) formed is, 0.0396 mol

8 0
3 years ago
Consider the cell notation Cd(s) | Cd(NO3)2(aq) || AgNO3(aq) | Ag(s) with standard reduction potentials for Cd2+ and Ag+ as -0.4
MakcuM [25]

The value of the Gibbs free energy shows us that the reaction is spontaneous.

<h3>What is the Gibbs free energy?</h3>

The Gibbs free energy is a quantity that helps us to be able to determine the spontaneity of a reaction.

In order to obtain the Gibbs free energy, we must obtain the Ecell as follows; 0.799V - (-0.402V) = 1.201 V

Now;

△G = -nFEcell

△G = -(2 * 96500 * 1.201)

△G = -232kJ/mol

Learn more about free energy:brainly.com/question/15319033?

#SPJ1

8 0
1 year ago
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