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3 years ago

When calculating percent error, the accepted value is in the denominator True or false

Chemistry

2 answers:

kaheart [24]3 years ago

8 0

Answer:

True

Explanation:

AVprozaik [17]3 years ago

6 0

The answer is TRUE

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SKILL: MAKING VALID GENERALIZATIONS Use the paragraph below to answer the following questions. The Chinese people also call the

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Answer:

Hope this helps

Explanation:

A generalization I can make about the Huang River is that the Huang River is the most important river in China. Also called the Yellow River, it is where historians believe ancient Chinese people settle in to develop its civilization on the banks of the river for the many benefits it had for life and agriculture. However, early Chinese people had to learn how to control the floods of the river in order to survive ad prosper.

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The answer is an answer

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Determine the molarity of a 6.0 mole% sulfuric acid solution with SG-a 1.07 Note: Atomic Weight: S (32), O 16); H (O)

marin [14]

Answer:

The molarity of a 6.0 mole% sulfuric acid solution is 2.8157 Molar.

Explanation:

Suppose there are 100 moles in solution:

Moles of sulfuric acid = 6% of 100 moles = 6 moles

Mass of 6 moles of sulfuric acid = 6 mol × 98 g/mol=588 g

Moles of water = 100%- 6% = 94%= 94 moles

Mass of water = 94 mol × 18 g/mol = 1692 g

Specific gravity of the solution ,S.G= 1.07

Density of solution = D

$S.G=\frac{D}{d_w}$

$d_w$ = density of water = 1 g/mL

$D=S.G\times d_w=1.07\times 1 g/mL=1.07 g/mL$

Mass of the solution = 588 g + 1692 g = 2280 g

Volume of the solution = V

Volume = $\frac{Mass}{Density}$

$=\frac{2280 g}{1.07 g/mL}=2130.84 mL=2.13084 L$

1 mL = 0.001 L

$Molarity = \frac{n}{V(L)}$

n = number of moles of compound

V = volume of the solution in L

here we have ,n = 6 moles of sulfuric acid

V = 2.13084 L

So, the molarity of the solution is :

$Molarity=\frac{6 mol}{2.13084 L}=2.8157 mol/L$

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