Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
7 hours and 15 minutes
Step-by-step explanation:
8 - 3/4 = 7 1/4 hours
Because change in y for the rise is if it goes up or down and change in x for the run to see if it goes left or right
Answer:
If you multiply the numbers you will get
0.030634
Answer:
112 students
Step-by-step explanation:
Let T be the total number of students in the band.
From the question,
We were told that 37.5% of the total owns their individual instruments and this amount to 42 students
The total number of students can calculated for as follows:
37.5% x T = 42
37.5/100 x T = 42
Cross multiply to express in linear form
37.5 x T = 100 x 42
Divide both side by 37.5
T = (100 x 42) /37.5
T = 112
Therefore, there are 112 students in the band