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Nostrana [21]
2 years ago
10

Just please help me, im trying to cram multiple things at once (house is crazy) and I just cant seem to concentrate and understa

nd these.

Mathematics
2 answers:
Anastasy [175]2 years ago
5 0
Y=31.2
X=15.6

I rounded both to the nearest tenth place.
nikdorinn [45]2 years ago
3 0

Answer:

Step-by-step explanation:

here is how you find the answer

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

now apply the above rules to the given triangle

where we are given the angle of 30°  and the Adj side of 27

y is the Hyp of this triangle and x is the Opp side of this triangle, now plug in the given values  as follows

so use CAH   Cos(30) = 27 / Hyp

Hyp = 27 / Cos(30)

Hyp = 27 / (\sqrt{3} / 2)

Hyp = 27 * 2 /  \sqrt{3}

Hyp = 54 / \sqrt{3}

y = 54 / \sqrt{3}

use SOH, since we know the exact value for the Hyp from above

Sin(30) = Opp / ( 54 / \sqrt{3}  )

Sin(30) * 54 / \sqrt{3}  = Opp

1/2 * 54 / \sqrt{3}  = Opp

27 / \sqrt{3}  = Opp

x = 27 / \sqrt{3}

:)

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11x + 2y = 68 & 5x + y = 13
matrenka [14]

Answer:

i hope its correct

Step-by-step explanation:

11x + 2y=68 ------------1

5x+y=13 ------------2

y= 13-5x. ------------3

put 3 into 1

11x +2(13-5x) =68

11x +26 -10x =68

x=42

put x =42 into 2

5(42) +y =13

210+y=13

y=13-210

y=197

4 0
3 years ago
What is 7.8 as a fraction?
Inessa05 [86]
7 & 8/10 or 78/10 ( which is the same thing)
5 0
3 years ago
Please help will give branliest
NikAS [45]

-2x+8y-3

Hope this helps! :)

3 0
2 years ago
Read 2 more answers
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
Which digit is in the hundred millions place in the number 465,382,109,728
Allisa [31]
3 is in the hundred millions
7 0
3 years ago
Read 2 more answers
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