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Lyrx [107]
3 years ago
15

Imagine a small child whose legs are half as long as her parent’s legs. If her parent can walk at maximum speed V, at what maxim

um speed can the child walk?
Physics
1 answer:
AnnZ [28]3 years ago
8 0

Answer:

\boxed{v=\frac {V}{\sqrt {2}}}

Explanation:

We know that speed is given by dividing distance by time or multiplying length and frequency. The speed of the father will be given by Lf where L is the length of the father’s leg ad f is the frequency.

We know that frequency of simple pendulum follows that f=\frac {1}{2\pi} \sqrt {\frac {g}{l}}

Now, the speed of the father will be V=Lf= L\times (\frac {1}{2\pi} \sqrt {\frac {g}{l}}) while for the child the speed will be v=\frac {L}{2}\times (\frac {1}{2\pi} \sqrt {\frac {g}{0.5l}})

The ratio of the father’s speed to the child’s speed will be

\frac {V}{v}=\frac {\frac {L}{2}\times (\frac {1}{2\pi} \sqrt {\frac {g}{0.5l}})}{ L\times (\frac {1}{2\pi} \sqrt {\frac {g}{l}})}\\\frac {V}{v}=\frac {\sqrt {2}}{2}\\\boxed{v=\frac {V}{\sqrt {2}}}

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masha68 [24]

Answer:

option C

Explanation:

given,

Temperature of the surface = 6000 K

using formula to calculate \lambda_{max}

\lambda_{max} = \dfrac{0.0029\ K.m}{T}

\lambda_{max} is the maximum wavelength emission in meter.

T is the temperature in kelvin.

\lambda_{max} = \dfrac{0.0029}{6000}

\lambda_{max} = \dfrac{0.0029}{6000}

\lambda_{max} = 4.8333 \times 10^{-7}

\lambda_{max} = 4833\ A^0

the wavelength is in Visible range

The Correct answer is option C

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3 years ago
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ziro4ka [17]

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4 0
3 years ago
Read 2 more answers
A 200N force pushes forward on the 20kg truck. The truck pulls two crates connected together by ropes, as shown. The gravitation
devlian [24]

Force on left crate, right crate and truck we need to draw here

First we will write the equation for left crate

T_{left} = m*a

T_{left} = 20*a

Now similarly for right crate

T_{right} - T_{left} = 20*a

now for truck

F - T_{right} = 20*a

Now we know that F = 200 N

200 - T_{right} = 20*a

now add all three equation

T_{left} + T_{right} - T_{left} + 200 - T{right} = 20a + 20 a + 20a

200 = 60 a

a = 10/3 m/s^2

now we will find all tension using this value of acceleration

T_{left} = 20 * \frac{10}{3} = \frac{200}{3} N

T_{right} - \frac{200}{3} = 20*\frac{10}{3}

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6 0
3 years ago
which would be better suited for agriculture, the soil of a tropical rain forest or that of a temperate deciduous forest
Romashka-Z-Leto [24]
I think it may be that of a temperate deciduous forest tho im not sure
thank u for letting me answer and god bless have a good life <3
6 0
3 years ago
A 65-kg bungee jumper, who is attached to one end of an 85-m long bungee cord that has its other end tied to a bridge, jumps off
irinina [24]

Answer:

The impulse delivered to the bungee jumper is 1.32 kN.s

Explanation:

The situation can be shown graphically as shown in the figure.

Impulse delivered to the bungee jumper = Area under the curve.

The curve represents a triangle and the area of traiangle = (1/2)base×height

The base of the triangle from the graph = 1.2 seconds.

The height of the triangle from the graph = 2.2 kN

Thus,

<u>Impulse = (1/2)×(1.2 seconds)×(2.2 kN) = 1.32 kN.s</u>

3 0
3 years ago
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