Which substance is a combination of different atoms?

What is the de Broglie wavelength of an object with a mass of 2.50 kg moving at a speed of 2.70 m/s? (Useful constant: h = 6.63×

xxMikexx [17]

Answer:

9.82 × $10^{-35}$ Hz

Explanation:

De Broglie equation is used to determine the wavelength of a particle (e.g electron) in motion. It is given as:

λ = $\frac{h}{mv}$

where: λ is the required wavelength of the moving electron, h is the Planck's constant, m is the mass of the particle, v is its speed.

Given that: h = 6.63 × $10^{-34}$ Js, m = 2.50 kg, v = 2.70 m/s, the wavelength, λ, can be determined as follows;

λ = $\frac{h}{mv}$

= $\frac{6.63*10^{-34} }{2.5*2.7}$

= $\frac{6.63 * 10^{-34} }{6.75}$

= 9.8222 × $10^{-35}$

The wavelength of the object is 9.82 × $10^{-35}$ Hz.

4 0

3 years ago

The graphs display velocity data Velocity is on the y-axis (m/s), while time is on the x-axis (s). Based on the graphs, which da

RUDIKE [14]

Answer:

The first graph is showing the constant acceleration (1 m/s)

Explanation:

The second graph showing the flexible velocity therefore a in the graph is different at t1, t2, t3, t4

The last graph is showing constant velocity therefore there is no acceleration (a = 0)

5 0

3 years ago

Read 2 more answers

Andrew is pushing this block to the right across on the floor. Which force in the free body diagram is pointing in the wrong dir

soldier1979 [14.2K]

Answer:

the normal force

Explanation:

The free-body diagram represents all the forces acting on an object. In this example, there are four forces acting on the box: an applied force, the friction (which always act opposite to the applied force), the weight of the box (which is always downward), and the normal force.

The normal force is the reaction force exerted by the surface on which the box is moving on the box, and this reaction force is always opposite to the force exerted by the box on the surface. Since the latter is downward, it means that the normal force must be upward, so in the diagram it is wrong.

8 0

3 years ago

Read 2 more answers

A 21500 kg jet airplane is flying through some high winds. At some point in time, the airplane is pointing due north, while the

GalinKa [24]

Answer: $\theta =79.47 North\ of\ west$

Explanation:

Given

Mass of airplane =21500 kg

Force due to jet engines=35100 N

Force from wind is 14900 N at angle of 75 south of west

Resolving forces

$F_x=14900cos75=-3856.403 N$

$F_y=35100-14900sin75$

$F_y=35100-14392.29=20707.70 N$

Therefore acceleration in x direction

$a_x=\frac{F_x}{m}=\frac{-3856.403}{21500}=-0.179 m/s^2$

$a_y=\frac{F_y}{m}=\frac{20707.70}{21500}=0.963 m/s^2$

Direction of acceleration

$tan\theta =\frac{a_y}{a_x}=\frac{0.963}{0.179}=-5.38$

$\theta =79.47\ North\ of\ west$

5 0

4 years ago

A man travels a distance if 1.5 m towards east ,then 2m towards south and 4.5 m towards east.

diamong [38]

Answer:

Explanation:

i) The total distance traveled will be the sum total of individual distances traveled by the man.

If the man travels a distance if 1.5 m towards east ,then 2m towards south and 4.5 m towards east, the total distance traveled will be expressed as; 1.5m+2m+4.5m

= 8.0m

ii) In order to get the man resultant displacement, we will use the Pythagoras theorem. Since the man travels a distance if 1.5 m and 4.5m towards east, the total distance taken towards east will be 6.0m and the distance traveled towards south is 2.0m. The resultant displacement of the man is expressed as;

R = $\sqrt{x^{2}+y^{2} }$

Note that the eastward direction is the x-direction while the south direction is the y-direction.

x = 6.0m and y = 2.0m

$R = \sqrt{6^{2}+2^{2} } \\R = \sqrt{36+4}\\ R = \sqrt{40} \\R = 6.32m$

The displacement of the man is 6.32m

4 0

3 years ago