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Maru [420]
4 years ago
15

Ultraviolet radiation is dangerous because it has a high enough energy to damage skin cells. What is the BEST explanation of the

relationship between wavelength and wave energy? A) Wave energy is related only to frequency, not wavelength. B) Longer wavelengths have lower frequencies but higher energy. C) The shorter the wavelength, the lower the frequency and the higher the energy. D) The shorter the wavelength, the higher the frequency and the higher the energy.
Physics
1 answer:
MrRissso [65]4 years ago
5 0

The answer is shorter the wavelength, higher the frequency and higher the energy.

<u>Explanation:</u>

The sun radiates UV energy in a wide range of wavelength, which are invisible to human eyes. The shorter the wavelength, the more energetic the radiation, and the greater the potential for harm.

The relationship between wavelength and wave energy is shorter the wavelength, higher the frequency and higher the energy.

It has a frequency ranges from 8 × 10^14 to 3 × 10^16 cycles per second, or hertz (Hz), and wavelengths id about 380 nanometers to about 10 nm.

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A box sits on the back of a flatbed truck. If the coefficient of static friction between the box and the truck bed is μs = 0.400
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Answer:

28,699m

Explanation:

The force to make the box move should be <u>μs.N=μs.m.g=m.</u><u>|</u><u>a</u><u>|</u>

then,

|a|=μs.g

Being

μs coefficient of static friction,

N the force made by the truck on the box caused by the gravity force,

m the mass,

g the acceleration of gravity

and a the acceleration of the truck.

x = v \times t  +  \frac{1}{2} \times a \times   {t}^{2}

as the truck is stopping, the acceleration is negative. then,

x = v \times t  -  \frac{1}{2} \times  |a| \times   {t}^{2}

|a|  = v  \div  t \\ t = v \div   |a|

x = v \times (v \div   |a| ) -  \frac{1}{2} \times  |a| \times   {(v \div   |a|)}^{2}

x = v \times (v \div  μs.g ) -  \frac{1}{2} \times  |a| \times   {(v \div   μs.g)}^{2}

x =   \frac{{v}^{2}}{μs \times g} -  \frac{1}{2} \times  \frac{{v}^{2}}{μs \times g} \\ x = \frac{1}{2} \times  \frac{{v}^{2}}{μs \times g} \\ x = 0.5 \times  \frac{{(15m/s) }^{2} }{0.4 \times 9.8m/ {s}^{2} }  = 28.699m

28,699m

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