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spayn [35]
2 years ago
6

What would be the distance moved if we had a 70 n force and work done is 8j

Physics
1 answer:
Lostsunrise [7]2 years ago
3 0

Answer:

0.1143m

Explanation:

W=f×s

8=70s

make s the subject of the formula

s=8/70

=0.1143m

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How can citizen -scientists help with the prediction of future earthquakes
iVinArrow [24]

Answer:

Avoid downed power lines and stay away from buildings and bridges from which heavy objects might fall during an aftershock. Stay away until local officials tell you it is safe. A tsunami is a series of waves that may continue for hours. Do not assume that after one wave the danger is over.

3 0
3 years ago
When an electric stove element is hot enough, it gives off a dull red glow. When it cools to the point that it no longer glows,
DochEvi [55]

Answer:

It will have a longer wavelength

Explanation:

When an electric stove is hot and gives dull red glow. a part of the energy dissipated is emitted as visible light and part as infrared radiation in the form of heat. When the stove cools down, and no longer glows all the energy is now in the form of infrared radiation.In the electromagnetic spectrum infrared rays have a higher wavelength than visible light. Hence for the reason the radiation will have a higher wavelength since visible light is cut off.

4 0
2 years ago
A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is
harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

Where,

d_g = Depth of glass

n_w = Refraction index of water

n_g = Refraction index of glass

n_{air} = Refraction index of air

d_w = Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})

d'w = 4.041cm

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

3 0
3 years ago
Write a list of at least five scientific methods.
kolbaska11 [484]
1- You should always have a question for your experiment.
2- You need to conduct background research. It helps to write down your sources so you can cite your references. 
3- Propose a hypothesis (educated guess on what you believe the outcome of the experiment will be)
4- Design and perform an experiment to test your hypothesis (include independent and dependent variable)
5- Record observations and analyze what the data means.
6- Conclude whether you need to accept or reject your hypothesis, which accepting means your hypothesis was right and rejected is if it was wrong. 
3 0
3 years ago
A typical electric refrigerator has a power rating of 500 Watts, which is the rate (J/s) at which electrical energy is supplied
Goshia [24]

Answer:

The rate of heat removed from inside the refrigerator is 300 watts.

Explanation:

By the First Law of Thermodynamics and the definition of a Refrigeration Cycle, we have the following formula to determine the rate of heat removed from inside the refrigerator (\dot Q_{L}), in watts:

\dot Q_{L} = \dot Q_{H}-\dot W (1)

Where:

\dot Q_{H} - Rate of heat released to the room, in watts.

\dot W - Rate of electric energy needed by the refrigerator, in watts.

If we know that \dot Q_{H} = 800\,W and \dot W = 500\,W, then the rate of heat removed from inside the refrigerator is:

\dot Q_{L} = \dot Q_{H}-\dot W

\dot Q_{L} = 300\,W

The rate of heat removed from inside the refrigerator is 300 watts.

3 0
2 years ago
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