Answer:
<em>LED;</em>
The energy of photons emitted by an LED is dictated by the band gap of the semiconductor used – the energy required to make an electron–hole pair. When an electron and hole recombine in a radiative process, a photon carries away the extra energy.
<u><em>BULB</em></u>
In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. ... 1, chemical potential energy is converted to electrical energy, which is immediately converted to light energy and heat energy
This flow of charge converts chemical potential energy into electrical energy. In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. bulb have a fillament but LED have no filament they produce energy through clod process but bulb have a filament and they produce energy through hot process
Explanation:
This progression of charge changes over substance expected vitality into electrical vitality. In the light, the progression of charge through the fiber warms it up and makes it shine. Along these lines, the light believers electrical vitality to warm vitality and light vitality.
hope soo u can understand my point
Answer:
Velocity of electron will be 
Explanation:
We have given distance across the plate d = 2 mm 
Potential difference V = 6 volt
We know that potential difference at any distance is given by
V = Ed , here V is potential difference, E is electric field and d is distance
So 
Charge on electron 
We know that expression of velocity is given by 
, here q is charge on electron, E is electric field and d is distance
So 
Explanation:
Solution:
Let the time be
t1=35min = 0.58min
t2=10min=0.166min
t3=45min= 0.75min
t4=35min= 0.58min
let the velocities be
v1=100km/h
v2=55km/h
v3=35km/h
a. Determine the average speed for the trip. km/h
first we have to solve for the distance
S=s1+s2+s3
S= v1t1+v2t2+v3t3
S= 100*0.58+55*0.166+35*0.75
S=58+9.13+26.25
S=93.38km
V=S/t1+t2+t3+t4
V=93.38/0.58+0.166+0.75+0.58
V=93.38/2.076
V=44.98km/h
b. the distance is 93.38km
What it looks to be that you found in A was the "initial"...b/c the question asks:
<span>"how much energy does the electron have 'initially' in the n=4 excited state?" </span>
<span>"final" would be where it 'finally' ends up at, ie. its last stop...as for this question...the 'ground state' as in its lowest energy level. </span>
The answer comes to: <span>−1.36×10^−19 J</span>
You use the same equation for the second part as for part a.
<span>just have to subract the 2 as in the only diff for part 2 is that you use 1squared rather than 4squared & subract "final -initial" & you should get -2.05*10^-18 as your answer. </span>
Answer:
The pulling force that acts along a stretched flexible connector, such as a rope or cable, is called tension, T. When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.
