Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
Answer:
they deleted my answer :(
Step-by-step explanation:
Answer:
30
Step-by-step explanation:
since the 2 sides are congruent, the two angles are congruent, so
75+75+ x= 180
150+x=180
x=30
Answer:
$6.4
Step-by-step explanation:
You just do 32 × .2 to give you the discount of 6.4
You multiple by .2 because 20% as a decimal is .2 ( you do 20% divided by 100 to give you .2)
Answer: 1/2
Step-by-step explanation:
1/3 = 2/6 so 2/6 + 1/6 = 3/6
3/6 = 1/2
