All categories

3 years ago

A giant star has a luminosity of 300 its color is most likely to be

1 answer:

amm18123 years ago

5 0

<span>The correct answer is blue. If you look at a luminosity star chart, called the Hertzsprung Russell Diagram, you will see the measurement of luminosity on the left side, and you will see a curve of stars with different colors (which correlate to the colors of the stars). Look for 30 on the luminosity measurement (look between 1 and 100). Then, move horizontally across the diagram until you hit the stars, whose color will be blue. Thus, blue is the answer.</span>

You might be interested in

Jill leaves home and rides a distance of 70 km. It took her 2.5 hours. What is her speed?

Paraphin [41]

The answer is ...
28 km per hour

5 0

3 years ago

When does air become turbulent around a thrown ball?

Mrrafil [7]

B, good luck, hope this helps :)

5 0

3 years ago

A runner starts from rest and in 2 s reaches a speed of 7 m/s. If we assume that the speed changed at a constant rate (constant

PtichkaEL [24]

Answer:

$v=3.5\frac{m}{s}$

Explanation:

The average speed is defined as:

$v=\frac{\Delta x}{\Delta t}$

Using the equations for uniformly accelerated motion, we calculate the runner's acceleration:

$a=\frac{v_f-v_o}{2}\\a=\frac{7\frac{m}{s}-0\frac{m}{s}}{2s}\\a=3.5\frac{m}{s^2}$

Now, we can calculate the distance that the runner travels:

$\Delta x=v_0t+\frac{at^2}{2}\\\Delta x=(0\frac{m}{s})(2s)+\frac{3.5\frac{m}{s}(2s)^2}{2}\\\Delta x=7m$

Finally, we calculate the runner's average speed:

$v=\frac{7m}{2s}\\v=3.5\frac{m}{s}$

4 0

3 years ago

An object is dropped from a height of 75.0 m above ground level. (a) Determine the distance traveled during the first second. (b

lys-0071 [83]

Answer:

a)Distance traveled during the first second = 4.905 m.

b)Final velocity at which the object hits the ground = 38.36 m/s

c)Distance traveled during the last second of motion before hitting the ground = 33.45 m

Explanation:

a) We have equation of motion

S = ut + 0.5at²

Here u = 0, and a = g

S = 0.5gt²

Distance traveled during the first second ( t =1 )

S = 0.5 x 9.81 x 1² = 4.905 m

Distance traveled during the first second = 4.905 m.

b) We have equation of motion

v² = u² + 2as

Here u = 0, s= 75 m and a = g

v² = 0² + 2 x g x 75 = 150 x 9.81

v = 38.36 m/s

Final velocity at which the object hits the ground = 38.36 m/s

c) We have S = 0.5gt²

75 = 0.5 x 9.81 x t²

t = 3.91 s

We need to find distance traveled last second

That is

S = 0.5 x 9.81 x 3.91² - 0.5 x 9.81 x 2.91² = 33.45 m

Distance traveled during the last second of motion before hitting the ground = 33.45 m

3 0

4 years ago

Norma-Jean [14]

Magnets with the same polarity (N-N or S-S) repel one another along the same direction. This agrees to the common rule that like poles repel and unlike poles attract. Hope this answers the question. Have a nice day. Feel free to ask more questions.

7 0

4 years ago

Read 2 more answers