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deff fn [24]
2 years ago
15

Can black wholes be an exit to the universe,why or why not? (just curious).

Physics
2 answers:
Sidana [21]2 years ago
8 0
I really doubt because the universe is supposed to be infinite
Paul [167]2 years ago
4 0
Well, it's hard to say that. Black hole is still a mysterious object with GREAT gravitational pull, object with less than the speed of light just goes into it and never back. Black hole maybe a gateway for some other place, many scientist think, there could be a "White hole" for it's other end. If so, they behave like a wormhole, (like a tunnel, which connects two position by folding them into time-space)!!

It's still in debate, if you really like cosmology, Astronomy, and anything about celestial objects, then please PM me!!!

Hope this helps!
You might be interested in
PLEASE ANSWER ASAP!!!!!!!
Viefleur [7K]

Answer:

B. Mechanical energy= 50J+30J=80J

4 0
3 years ago
A record player turntable initially rotating at 3313 rev/min is braked to a stop at a constant rotational acceleration. The turn
Rus_ich [418]

Answer:

(A) It will take 22 sec to come in rest

(b) Work done for coming in rest will be 0.2131 J              

Explanation:

We have given the player turntable initially rotating at speed of 33\frac{1}{3}rpm=33.333rpm=\frac{2\times 3.14\times 33.333}{60}=3.49rad/sec

Now speed is reduced by 75 %

So final speed \frac{3.49\times 75}{100}=2.6175rad/sec

Time t = 5.5 sec

From first equation of motion we know that '

\alpha =\frac{\omega -\omega _0}{t}=\frac{2.6175-3.49}{4}=-0.158rad/sec^2

(a) Now final velocity \omega =0rad/sec

So time t to come in rest  t=\frac{0-3.49}{-0.158}=22sec

(b) The work done in coming rest is given by

\frac{1}{2}I\left ( \omega ^2-\omega _0^2 \right )=\frac{1}{2}\times 0.035\times (0^2-3.49^2)=0.2131J

4 0
2 years ago
What condition is necessary for the sustained flow of water in a pipe?
lianna [129]
Pressure difference (voltage)
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5 0
3 years ago
A bare helium nucleus has two positive charges and a mass of 6.64×10−27kg(a) Calculate its kinetic energy in joules at 2.00% of
grandymaker [24]

To solve this problem we will apply the concepts related to kinetic energy and energy conservation. The kinetic energy will be expressed in terms of mass and speed, as well as load and voltage. From this last expression we will find the charges by electron and by Helium nucleus.

a ) Kinetic Energy is given as

KE = \frac{1}{2} mv^2

Replacing with our values we have that

KE = \frac{1}{2} (6.64*10^{-27})(2.0\% (3.00*10^8))^2

KE = 1.1935*10^{-13}J

Therefore the kinetic energy of the helium nucleus is 1.1935*10^{-13}J

PART B) Now for calculate the electron volts we use the kinetic energy as a expression between the charge and the voltage, that is

KE = qV

Here,

q = Charge of an electron

V = Voltage

Rearranging to find the potential we have,

V = \frac{KE}{q}

V = \frac{1.19*10^{-13}}{1.6*10^{-19}}

V = 743750eV

Therefore the kinetic energy in electron vols is 743750eV

PART C) Applying the same relationship but now using the Helium core load, we will have to

KE = QV

Here,

Q = Charge of a helium nucleus

V = Voltage

Rearranging to find the potential we have

V = \frac{KE}{Q}

But we need to note that the charge is equal to the number of charge for the unit charge, then

Q = \text{No. Charge} \times \text{Unit Charge}

Q = (2)(1.6*10^{-19}C)

Q = 3.2*10^{-19}C

Now replacing we have that

V= \frac{1.19*10^{-13}}{32*10^{-19}}

V = 371875V

Therefore the voltage applied is  371875V

5 0
3 years ago
Who invented the atomic battery and what purpose does it serve
Nady [450]
Henry Moseley, its a generator which uses energy to generate electricity
6 0
3 years ago
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