Question

A plane electromagnetic wave travels northward. At one instant, its electric field has a magnitude of 3.7 V/m and points eastward. What are the magnitude (in T) and direction of the magnetic field at this instant

Answer 1

Answer:

Magnetic field, B = $1.24\times 10^{-8}\ T$ (eastwards)

Explanation:

Given that,

The magnitude of electric field, E = 3.7 V/m

A plane electromagnetic wave travels northward. We need to find the magnitude and direction of the magnetic field at this instant.

The relation between the magnetic field and the electric field of the plane electromagnetic wave is given by :

$B=\dfrac{E}{c}$

c is the speed of light

$B=\dfrac{3.7}{3\times10^8}\\\\B=1.24\times 10^{-8}\ T$

So, the magnetic field is $1.24\times 10^{-8}\ T$. The direction of magnetic field is perpendicular to the electric field and the direction of wave propagation. Hence, the direction of magnetic field is eastward.