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inessss [21]
3 years ago
7

It takes a bus driver 30 minutes to pick up students from four stops. The last stop is at the corner of Green Street and Route 7

0. The most direct route to school is north on Route 70. The speed limit on Route 70 is 35 kph. The bus driver wants to calculate the average velocity from the last stop to school.
Can this be done from the information given?


No, the distance from the last stop to the school and the time it takes to travel that distance are required.


No, the distance from the first stop to the school and the average speed are required.


Yes, if the average speed is 35 kph, and it takes 30 minutes, the average velocity is 17.5 kph.


Yes, if the speed limit is 35 kph, and the elapsed time is 30 minutes, the average velocity is 17.5 kph north
Physics
1 answer:
deff fn [24]3 years ago
7 0

Answer:

No, the distance from the last stop to the school and the time it takes to travel that distance are required.

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4000 Joules (if you mean 2000 kilograms)

Explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
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dezoksy [38]
Note: I'm not sure what do you mean by "weight 0.05 kg/L". I assume it means the mass per unit of length, so it should be "0.05 kg/m".

Solution:
The fundamental frequency in a standing wave is given by
f= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where L is the length of the string, T the tension and m its mass. If  we plug the data of the problem into the equation, we find
f= \frac{1}{2 \cdot 24 m} \sqrt{ \frac{240 N}{0.05 kg/m} }=1.44 Hz

The wavelength of the standing wave is instead twice the length of the string:
\lambda=2 L= 2 \cdot 24 m=48 m

So the speed of the wave is
v=\lambda f = (48 m)(1.44 Hz)=69.1 m/s

And the time the pulse takes to reach the shop is the distance covered divided by the speed:
t= \frac{L}{v}= \frac{24 m}{69.1 m/s}=0.35 s
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4 years ago
what was the mass of a cannkn ball whose velocity is 200m/s if it were shot from 1000kg that recoils a 2m/s. Solve step by step​
Whitepunk [10]

The famous Newton’s Third Law states that “For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.”

By using this,

10grams or 0.01kg of bullet with speed 400 m/sec and 5kg gun recoil with speed suppose ‘v’.

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Newtons third law (inertia) is to blame
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Read 2 more answers
What is the net force acting on a 52 kg object that has a velocity of 8.0 m/s and is moving in a circle of radius 1.6 m? a. 4000
jenyasd209 [6]
Σf = m a
Σf = m v^2 / r
Σf = 52 8^2 / 1.6
Σf = 2080 N
7 0
3 years ago
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