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beks73 [17]
3 years ago
11

X + y - 6 = 0 x - y - 8 = 0 When you eliminate y , what is the resulting equation?

Mathematics
2 answers:
Svet_ta [14]3 years ago
7 0
You get 2x-14=0

x+y-6=0
x-y-8=0
--------------   Then add the rest up
2x-14=0
alisha [4.7K]3 years ago
5 0
When we eliminate y,(by adding here), resulting equation would be:

2x - 14 =0

So, x = 7

You can find the value of y as well, by substituting the value of x, 
7 - y -8 = 0
y = -1

Hope this helps!
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\displaystyle\\&#10;1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) = ? \\  \\ &#10;1 \frac{2}{5} = \frac{1\times 5+2}{5}=\boxed{\frac{7}{5}} \\  \\ &#10;-5 \frac{1}{2} =-5 -\frac{1}{2} = \frac{-5\times2-1}{2} =\frac{-10-1}{2}=\frac{-11}{2}= \boxed{-\frac{11}{2} }\\  \\ \texttt{OR} \\  \\ &#10;-5 \frac{1}{2} = -\Big(5 \frac{1}{2} \Big)= -\Big( \frac{5\times2+1}{2} \Big)=-\Big( \frac{11}{2} \Big)= \boxed{-\frac{11}{2} }


\displaystyle\\&#10;\Longrightarrow ~~1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) =\frac{7}{5} -\frac{11}{2} = \frac{7\times 2}{5\times 2} -\frac{11\times 5}{2\times 5} = \\  \\ &#10;= \frac{14}{10} -\frac{55}{10} = \frac{14-55}{10} =\frac{-41}{10} = -\frac{41}{10}=-\frac{40+1}{10}=\boxed{\boxed{-4\frac{1}{10}}}



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