2.87mL of 2.5 M K2SO4 are required to obtain 1.25 grams of the compound.
<h3>HOW TO CALCULATE VOLUME?</h3>
The volume of a substance can be calculated by dividing the number of moles of the substance by its molarity. That is;
volume = no. of moles ÷ molarity
According to this question, 2.5M K2SO4 are required to obtain 1.25 grams of the compound. The volume can be calculated as follows:
Molar mass of K2SO4 = 174.26 g/mol
moles of K2SO4 = 1.25g ÷ 174.26g/mol
moles of K2SO4 = 0.00717moles
Volume = 0.00717moles ÷ 2.5
Volume = 0.00287 L = 2.87mL.
Therefore, 2.87mL of 2.5 M K2SO4 are required to obtain 1.25 grams of the compound.
Learn more about volume at: brainly.com/question/1578538
Answer:
A.) 34.866 x 10¯23 g/atom
B.) 2.64 x 10^22 atoms in 1 cm3
C.) 1 atoms per unit cell
Explanation:
A) Calculate the average mass of one atom of polonium:
210g mol¯1 ÷ 6.022 x 1023 atoms mol¯1 = 34.866 x 10¯23 g/atom
B) Determine atoms in 1 cm3:
9.19g / 34.866x 10¯23 g/atom = 2.64 x 10^22 atoms in 1 cm3
Determine volume of the unit cell:
(3.37 x 10¯8 cm)3 = 3.827 x 10¯23 cm3
Determine number of unit cells in 1 cm3:
1 cm3 / 3.827 x 10¯23 cm3 = 2.61 x 1022 unit cells
C) Determine atoms per unit cell:
2.64 x 1022 atoms / 2.61 x 1022 unit cells = 1 atoms per unit cell
Answer:
atom is the smallest unit of ordinary matter that forms a chemical element. Every solid, liquid, gas, and plasma is composed of neutral or ionized atoms. Atoms are extremely small, typically around 100 picometers across.
To answer the question above, let us a basis of the 1000 mL or 1 L.
volume = (0.9928 g/mL)(1000mL) = 992.8 g
Then, determine the mass of the alcohol by multiplying the total mass by the decimal equivalent of 5%.
mass of alcohol = 0.05(992.8 g) = 49.64 g
Then, determine the number of moles of ethyl alcohol by dividing the mass of alcohol by the molar mass (46 g/mol).
n = 49.64 g/ (46 g/mol) = 1.08 mol
Then, divide the number of moles by the volume (our basis is 1 L)
molarity = 1.08 mol/ 1 L = 1.08 M
Answer:
Explanation:
In CF4 and NF3, the valence electron groups on the central C and N atoms have a tetrahedral arrangement. The shapes of the molecules are determined by the number of bonding and nonbonding of electrons: since CF4 has four bonded atom(s) and zero lone pair(s) of electrons, the shape is tetrahedral.
