0.012 mol of CO₂ is the volume of CO₂ is produced from 1.00 g of baking powder.
Balanced Equation:
Ca(H₂PO₄)₂(s) + 2NaHCO₃(s) → 2CO₂(g) + 2H₂O(g) + CaHPO₄(s) + Na₂HPO₄(s)
On 3.50 g of baking powerd:
mCa(H₂PO₄)₂ = 0.35*3.50 = 1.225 g
mNaHCO₃ = 0.31*3.50 = 1.085 g
The molar masses are: Ca = 40 g/mol; H = 1 g/mol; P = 31 g/mol; O = 16 g/mol; Na = 23 g/mol; C = 12 g/mol. So:
Ca(H₂PO₄)₂: 40 + 4x1 + 31 + 8x16 = 203 g/mol
NaHCO₃: 23 + 1 + 12 + 3x16 = 84 g/mol
The mass divided by the molar mass yields the number of moles, as in:
nCa(H₂PO₄)₂ = 1.225/203 = 0.006 mol
nNaHCO₃ = 1.085/84 = 0.0129 mol
Find the reactant that is limiting first. The stoichiometry for the Ca(H₂PO₄)₂ test is:
1 mol of Ca(H₂PO₄)₂ ---------- 2 mol of NaHCO₃
0.006 of Ca(H₂PO₄)₂ -------- x
By a simple direct three rule:
x = 0.012 mol
NaHCO₃ is therefore too much. After performing the stoichiometry calculus with the limiting reactant:
1 mol of Ca(H₂PO₄)₂ ------------- 2 mol of CO₂
0.006 of Ca(H₂PO₄)₂ -------- x
By a simple direct three rule:
x = 0.012 mol of CO₂
What is molar mass and how is it calculated?
The mass of every atom in a molecule, expressed in grams per mole, is known as the molar mass. We first obtain the atomic weights of the different elements in a periodic table in order to compute the molar mass of a molecule. Then, we multiply the total number of atoms by each one's atomic mass.
How is molar mass calculated and why is it important?
When converting a mass measurement to a substance amount, the molar mass ratio is utilized. The number of atoms, molecules, or ions that make up this quantity is used to express it. It is the proportion of an object's mass to the quantity of its constituent particles.
Learn more about molar mass: brainly.com/question/13152455
#SPJ4
