Question

Calcium dihydrogen phosphate, Ca(H₂PO₄)₂, and sodium hydrogen carbonate, NaHCO₃, are ingredients of baking powder that react to produce CO₂, which causes dough or batter to rise:
Ca(H₂PO₄)₂ (s) + NaHCO₃(s) →
CO₂(g) + H₂O(g) + CaHPO₄(s) + NaHPO₄(s)
[unbalanced]
If the baking powder contains 31% NaHCO3 and 35% Ca(H₂PO₄)₂ by mass:
(b) If 1 mol of CO₂ occupies 37.0 L at 350°F (a typical baking temperature), what volume of CO₂ is produced from 1.00 g of baking powder?

Answer 1

0.012 mol of CO₂ is the volume of CO₂ is produced from 1.00 g of baking powder.

Balanced Equation:

Ca(H₂PO₄)₂(s) + 2NaHCO₃(s) → 2CO₂(g) + 2H₂O(g) + CaHPO₄(s) + Na₂HPO₄(s)

On 3.50 g of baking powerd:

mCa(H₂PO₄)₂ = 0.35*3.50 = 1.225 g

mNaHCO₃ = 0.31*3.50 = 1.085 g

The molar masses are: Ca = 40 g/mol; H = 1 g/mol; P = 31 g/mol; O = 16 g/mol; Na = 23 g/mol; C = 12 g/mol. So:

Ca(H₂PO₄)₂: 40 + 4x1 + 31 + 8x16 = 203 g/mol

NaHCO₃: 23 + 1 + 12 + 3x16 = 84 g/mol

The mass divided by the molar mass yields the number of moles, as in:

nCa(H₂PO₄)₂ = 1.225/203 = 0.006 mol

nNaHCO₃ = 1.085/84 = 0.0129 mol

Find the reactant that is limiting first. The stoichiometry for the Ca(H₂PO₄)₂ test is:

1 mol of Ca(H₂PO₄)₂ ---------- 2 mol of NaHCO₃

0.006 of Ca(H₂PO₄)₂ -------- x

By a simple direct three rule:

x = 0.012 mol

NaHCO₃ is therefore too much. After performing the stoichiometry calculus with the limiting reactant:

1 mol of Ca(H₂PO₄)₂ ------------- 2 mol of CO₂

0.006 of Ca(H₂PO₄)₂ -------- x

By a simple direct three rule:

x = 0.012 mol of CO₂

What is molar mass and how is it calculated?

The mass of every atom in a molecule, expressed in grams per mole, is known as the molar mass. We first obtain the atomic weights of the different elements in a periodic table in order to compute the molar mass of a molecule. Then, we multiply the total number of atoms by each one's atomic mass.

How is molar mass calculated and why is it important?

When converting a mass measurement to a substance amount, the molar mass ratio is utilized. The number of atoms, molecules, or ions that make up this quantity is used to express it. It is the proportion of an object's mass to the quantity of its constituent particles.

Learn more about molar mass: brainly.com/question/13152455

#SPJ4