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GenaCL600 [577]
3 years ago
10

Simplify: (3x – 1) (x3 + 2x + 1)

Mathematics
2 answers:
Naddik [55]3 years ago
7 0

Answer:

3x^4-x^3+6x^2+x-1

Step-by-step explanation:

Distribute parentheses:

3xx^3 + 3x * 2x + 3x * 1 + (-1)x^3 + (-1) * 2x + (-1) * 1

Add minus and plus rules:

3x^3x + 3 * 2xx + 3 * 1 * x - 1 * x^3 - 1 * 2x - 1 * 1

Simplify:

3x^4-x^3+6x^2+x-1

pshichka [43]3 years ago
5 0

Answer:

B: 3x4-x3+6x2+x-1

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<h2>Exponential Functions</h2>

Exponential functions are typically organized in this format:

f(x) = a*c^x

To find the equation given the graph of an exponential function:

  1. Identify the horizontal asymptote
    ⇒ <em>asymptote</em> - a line towards which a graph appears to travel but never meets
    ⇒ If the horizontal asymptote is not equal to 0, we add this at the end of the function equation.
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<em />

<h2>Solving the Question</h2>

Identify the horizontal asymptote

In this question, it appears to be x = 0.

Identify the y-intercept

The y-intercept is the value of <em>y</em> at which the graph appears to cross the y-axis. In this graph, it appears to be 100. This is our <em>a</em> value. Plug this into f(x) = a*c^x:

f(x) = 100*c^x

Solve for <em>c</em>

We can use any point that falls on the graph for this step. For instance, (1,50) appears to be a valid point. Plug this into our equation and solve for <em>c</em>:

f(x) = 100*c^x\\50 = 100*c^1\\50 = 100*c\\\\c=\dfrac{1}{2}

Plug <em>c</em> back into our original equation:

f(x) = 100*(\dfrac{1}{2})^x

<h2>Answer</h2>

f(x) = 100*(\dfrac{1}{2})^x

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Step-by-step explanation:

On a linear equation there's only <u>1 dependent variable</u> and this <u>cannot</u> be under a radical or exponent different than 1. Therefore, te only linear equations within the options are B and C.

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katen-ka-za [31]

Answer:

352

Step-by-step explanation:

(216-128)*(4)

(88)*(4)

352

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