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3 years ago

Simplify: (3x – 1) (x3 + 2x + 1)

Mathematics

2 answers:

Naddik [55]3 years ago

7 0

Answer:

$3x^4-x^3+6x^2+x-1$

Step-by-step explanation:

Distribute parentheses:

$3xx^3 + 3x * 2x + 3x * 1 + (-1)x^3 + (-1) * 2x + (-1) * 1$

Add minus and plus rules:

$3x^3x + 3 * 2xx + 3 * 1 * x - 1 * x^3 - 1 * 2x - 1 * 1$

Simplify:

$3x^4-x^3+6x^2+x-1$

pshichka [43]3 years ago

5 0

Answer:

B: 3x4-x3+6x2+x-1

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The graph of g(x) is a transformation of the graph of f(x)=4x .

Alenkasestr [34]

Answer:

g(x) = 4^x + 1.

Step-by-step explanation:

The graph of f(x) = 4^x passes through the point (0, 1) because when x = 0, 4*0 = 1. Also when x = 1, 4^x= 4. So it passes through (1, 4).

For g(x) we have corresponding points (0, 2) and (1, 5).

So we see that g(x) is a similar graph but it has been translated up 1 unit.

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3 years ago

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3 years ago

What is 2+2 and what is your favorite song?<br>

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Answer:

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Step-by-step explanation:

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3 years ago

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cho tứ giác ABCD. Gọi M,N,P,Q là trung điểm của các cạnh AB, CD, AD, BC. Chứng minh rằng vecto MP = vecto QN, vecto MQ = vecto P

Dmitriy789 [7]

Answer:

Step-by-step explanation:

Xét tam giác DAB có: P là trung điểm AD, M là trung điểm AB

=> MP là đường trung bình của tam giác DAB => MP//BD và MP= $\frac{1}{2}$ BD (1)

Xét tam giác DBC có: N là trung điểm DC, Q là trung điểm BC

=> QN là đường trung bình của tam giác DBC => QN//BD và QN= $\frac{1}{2}$ BD (2)

Từ (1) và (2) => vecto MP song song cùng chiều với vecto QN

và độ dài MP = độ dài QN = $\frac{1}{2}$ BD

=> vecto MP = vecto QN

Tương tự xét các tam giác DAC và tam giác ABC => vecto MQ = vecto PN

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3 years ago

Steffie makes a scale drawing for a crate with the demensions 15 inches long by 12 inches wide. Her scale factor is 1:3. Brian m

rodikova [14]

Answer:

Dimensions → (5 inches × 4 inches)

Step-by-step explanation:

Scale factor used for the drawing by Steffie = $\frac{1}{3}$

Since, scale factor = $\frac{\text{Dimension of the drawing}}{\text{Actual dimension}}$

For Steffie,

Actual length of the crate = $\frac{\text{Dimension of the drawing}}{\text{Scale factor}}$

= $\frac{15}{\frac{1}{3}}$

= 45 inches

Actual width of the crate = $\frac{12}{\frac{1}{3} }$

= 36 inches

Since Brian used the scale factor = $\frac{1}{9}$

Length of the drawing = Actual length × Scale factor

= 45 × $\frac{1}{9}$

= 5 inches

Width of the drawing = Actual width × Scale factor

= 36 × $\frac{1}{9}$

= 4 inches

Therefore, dimensions of the drawing made by Brian are (5 inches × 4 inches)

6 0

3 years ago