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scoundrel [369]
3 years ago
13

40 points

Chemistry
2 answers:
amm18123 years ago
7 0

Answer:

I am so confused about this i am so sorry but i cant there is to much going on

Explanation:

Aliun [14]3 years ago
4 0

Sun2

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Treatment that uses drugs to stop the growth of cancer cells, either by killing the cells or by stopping them from dividing. Chemotherapy may be given by mouth, injection, or infusion, or on the skin, depending on the type and stage of the cancer being treated.

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3 years ago
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of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution is measu
krok68 [10]

The question is incomplete . The complete question is :

100 mg of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution is measured to be 0.107atm at 25.0°C. Calculate the molar mass of the protein. Round your answer to 3 significant digits.

Answer:  The molar mass of the protein is 4.57\times 10^3g/mol

Explanation:

\pi =CRT

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 0.107 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (protein) = 100 mg = 0.1 g   (Conversion factor: 1 g = 1000 mg)

Volume of solution = 5.00 mL

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

0.107=1\times \frac{0.1\times 1000}{\text{Molar mass of insulin}\times 5.00}\times 0.0821\text{ Latm }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of protein}

\text{molar mass of protein}=4.57\times 10^3g/mol

Hence, the molar mass of the protein is 4.57\times 10^3g/mol

7 0
3 years ago
3 The volume of a gas is 50.0 mL at 20.0 K. What will be the new
Damm [24]

Answer:

C. 4.00 K

Explanation:

We can solve this using Charles's Law of the ideal gas. The law describes that when the pressure is constant, the volume will be directly proportional to the temperature. Note that the temperature here should only use the Kelvin unit. Before compressed, the volume of the gas is 50ml(V1) and the temperature is 20K (T1). After compressed the volume becomes 10ml(V2). The calculation will be:

V1 / T1= V2 / T2

50ml / 20K = 10ml / T2

T2= 10ml/ 50ml * 20K

T2= 4K

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