Answer:
3.33m
Explanation:
Given parameters:
Force applied =500N
Elastic constant = 150N/m
Unknown:
Amount of stretch or extension = ?
Solution:
To solve this problem use the expression below:
F = k e
F is the force applied
k is the elastic constant
e is the extension
So;
500 = 150 x e
e = 
= 3.33m
Answer:
Explanation:
We shall represent vector B and C in terms of i and j .
B = 5 cos115 i + 5 sin115 j
= -2.11 i + 4.53j
Similarly
C = 4 cos255 i + 4 sin225 j
= -1.04 i -3.86 j
R = B + C
= -2.11 i + 4.53j -1.04 i -3.86 j
= -3.15 i + .67 j
magnitude of R
= √( 3.15² + .67² )
= √( 9.92 +.45 )
= 3.22
Angle Ф
TanФ = - .67 / 3.15
= - .21
Ф = - 12⁰
= 180 - 12
= 168 degree counterclockwise from positive x axis.
Answer:
A change has occurred in a nucleus
Answer:
115.3 is the direction of the vector. Just learned some physics to get this answer over the past 3 hrs
By Wind
By the Coriolis effect and land
Hope it helped
