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Leokris [45]
3 years ago
11

What is the specific heat of the solid phase? (Please see picture attached)

Chemistry
1 answer:
ValentinkaMS [17]3 years ago
4 0

Answer:

B.0.2 J/g°C

Explanation:

From the attached picture;

  • Heat attained in the solid phase is 200 Joules
  • Change in temperature is 50°C ( from 0°C to 50°C)
  • Mass of the solid is 20 g

We are required to determine the specific heat capacity of the substance;

  • We need to know that Quantity of heat is given by the product of mass,specific heat capacity and change in temperature.
  • That is; Q = mcΔT

Rearranging the formula;

c = Q ÷ mΔT

Therefore;

Specific heat = 200 J ÷ (20 g × 50°c)

                      = 0.2 J/g°C

Thus, the specific heat of the solid is 0.2 J/g°C

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Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
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Answer:

pH of resulting solution = 7.98

Explanation:

The balanced equation  

HA + NaOH - Na+ + A- + H2O

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= 35.8/1000 * 0.020 = 0.000716 mol

Initial concentration of A = 0.000716/0.0608 = 0.01178 M

pKb = 14 – pKa = 14 -3.9 = 10.1

Kb = 10^{-Kb} = 10^{-10.1} = 7.943 * 10^-11

Kb = [HA][OH-]/[A-]

Kb = a^2/(0.01178 -a) = 7.943 * 10^-11

a^2 + 7.943 * 10^-11 a – 9.357 * 10^-13 = 0

a = 9.673 * 10^-7

OH- = a = 9.673 * 10^-7 M

pOH = -log [OH-] = -log (9.673 * 10^-7) = 6.02

pH = 14-6.02 = 7.98

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3 years ago
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Answer:

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Explanation:

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Answer:

according to online:

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Explanation:

hope this helps!! :)

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