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3 years ago

What is the word eletrovent

Chemistry

1 answer:

djyliett [7]3 years ago

8 0

Answer:

Explanation:

Electrovalent is a word often associated with chemical bonding in the field of chemistry. It is special type of bond that occurs between metals and non-metals.

These bond types are interatomic interactions occurring between two atoms to ensure that they attain stable configurations.

This bond type is also known as ionic bonds.
It occurs between two species with a large electronegative diffference i.e one specie is electropositive and the other highly electronegative.
The more electropositive specie is metal and it readily loses its valence electrons.
The electronegative non-metal gains the electrons and becomes negatively charged.
The electrostatic attraction between the metal and non-metals yields the electrovalent bonds.

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How do different stimuli affect the survival behavior of an organism?

Vlad [161]

Organisms change their behavior in responses to changes in the environment.

All living things can respond to stimuli in the exterior environment, it is a form of energy-light waves or sound vibrations, From what they sense they will make necessary changes to their diet and or where they are located. Such as winter weather which is a type stimuli will cause some animals to start talking.

6 0

3 years ago

A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.9

rjkz [21]

Answer:

The mass % of BaCl2 is 47.24 %

Explanation:

Step 1: Data given

Molar mass BaSO4 = 233.38 g/mol

Molar mass BaCl2 = 208.23 g/mol

Step 2: The balanced equation

BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq)

Step 3: Calculate moles BaSO4

Moles BaSO4 = mass BaSO4 / molar mass BaSO4

Moles BaSO4 = 2.113 grams / 233.38 g/mol

Moles BaSO4 = 0.00905 moles

Step 4: Calculate moles BaCl2

For 1 mol BaCl2 we need 1 mol Na2SO4 to produce 1 mol BaSO4 and 2 moles NaCl

For 0.00905 moles BaSO4 we need 0.00905 moles BaCl2

Step 5: Calculate mass BaCl2

Mass BaCl2 = moles BaCl2 * molar mass BaCl2

Mass BaCl2 = 0.00905 moles *208.23 g/mol

Mass BaCl2 = 1.884 grams

Step 6: Calculate % BaCl2

% BaCl2 = (1.884 / 3.988 ) * 100%

% BaCl2 = 47.24 %

The mass % of BaCl2 is 47.24 %

7 0

3 years ago

What is the rate law for the uncatalyzed reaction?

elena55 [62]

What is the rate law for the uncatalyzed reaction?

Metals often form several cations with different charges. Cerium, for example, forms and ions, and thallium forms and ions. Cerium and thallium ions react as follows:

2Ce^4+(aq) + Tl^+(aq) ---> 2Ce^3+(aq)+Tl^3+(aq)

This reaction is very slow and is thought to occur in a single elementary step. The reaction is catalyzed by the addition of Mn^2+ according to the following mechanism:

Ce^4+(aq)+Mn^2+(aq) ---> Ce^3+(aq)+Mn^3+(aq)

Ce^4+(aq)+Mn^3+(aq) ---> Ce^3+ (aq) + Mn^4+ (aq)

Mn^4+(aq) + Tl^+(aq) ---> Mn^2+(aq) + Tl^3+(aq)

If the uncatalyzed reaction occurs in a single elementary step, why is it a slow reaction?

1)The probability of an effective three-particle collision is low.

2) The transition state is low in energy.

3) The reaction requires the collision of three particles with the correct energy and orientation.

4) All reactions that occur in one step are slow.

The catalyzed reaction is first order in [Ce^4+] and first order in [Mn^2+]. Which of the steps in the catalyzed mechanism is rate determining?

Based on their available oxidation states, rank the following metals on their ability to catalyze this and other oxidation-reduction reactions.

Rank from best to worst catalyst.

Vanadium, titanium, manganese

4 0

3 years ago

Read 2 more answers

A student is performing a titration to determine the concentration of a 20.0 mL sample of hydrochloric acid. What did the studen

irakobra [83]

Answer:

0.25M HCl

Explanation:

The reaction of HCl with NaOH is:

HCl + NaOH ⇄ H₂O + NaCl

<em>Where 1 mole of HCl reacts per mole of NaOH</em>

The end point was reached when the student added:

0.0500L × (0.1mol / L) = 0.00500 moles of NaOH

As 1 mole of HCl reacted per mole of NaOH, moles of HCl present are:

<em>0.00500 moles HCl</em>

The volume of the sample of hydrochloric acid was 20.0mL = 0.0200L, and concentration of the sample is:

0.00500 mol HCl / 0.0200L = <em>0.25M HCl</em>

8 0

3 years ago

Determine the molecular formula for each of the following compounds from the

bulgar [2K]

The molecular formula for each of the following compound given the data is

C₂H₆
C₂H₂
C₄H₈Cl₂

<h3>A. How to determine the molecular formula </h3>

We'll begin by calculating the empirical formula. This can be obtained as follow:

C = 80%
H = 20%
Empirical formula =?

Divide by their molar mass

C = 80 / 12 = 6.67

H = 20 / 1 = 20

Divide by the smallest

C = 6.67 / 6.67 = 1

H = 20 / 6.67 = 3

Thus, the empirical formula of the compound CH₃

Thus, the molecular formula of the compound can be obtained as follow

Empirical formula = CH₃
Molar mass of compound = 30 g/mol
Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Thus, the molecular formula of the compound is C₂H₆

<h3>B. How to determine the molecular formula </h3>

We'll begin by calculating the empirical formula. This can be obtained as follow:

C = 92.3%
H = 7.7%
Empirical formula =?

Divide by their molar mass

C = 92.3 / 12 = 7.7

H = 7.7 / 1 = 7.7

Divide by the smallest

C = 7.7 / 7.7 = 1

H = 7.7 / 7.7 = 1

Thus, the empirical formula of the compound CH

Thus, the molecular formula of the compound can be obtained as follow

Empirical formula = CH
Molar mass of compound = 26 g/mol
Molecular formula =?

Molecular formula = empirical × n = mass number

[CH]n = 26

[12 + 1]n = 26

13n = 26

Divide both side by 13

n = 26 / 13

n = 2

Molecular formula = [CH]n

Molecular formula = [CH]₂

Molecular formula = C₂H₂

Thus, the molecular formula of the compound is C₂H₂

<h3>C. How to determine the molecular formula </h3>

We'll begin by calculating the empirical formula. This can be obtained as follow:

C = 37.5%
H = 6.3%
Cl = 55.8%
Empirical formula =?

Divide by their molar mass

C = 37.5 / 12 = 3.125

H = 6.3 / 1 = 6.3

Cl = 55.8 / 35.5 = 1.572

Divide by the smallest

C = 3.125 / 1.572 = 2

H = 6.3 / 1.572 = 4

Cl = 1.572 / 1.572 = 1

Thus, the empirical formula of the compound C₂H₄Cl

Thus, the molecular formula of the compound can be obtained as follow

Empirical formula = C₂H₄Cl
Molar mass of compound = 127 g/mol
Molecular formula =?

Molecular formula = empirical × n = mass number

[C₂H₄Cl]n = 127

[(2×12) + (4×1) + 35.5]n = 127

63.5n = 127

Divide both side by 63.5

n = 127 / 63.5

n = 2

Molecular formula = [C₂H₄Cl]n

Molecular formula = [C₂H₄Cl]₂

Molecular formula = C₄H₈Cl₂

Thus, the molecular formula of the compound is C₄H₈Cl₂

Learn more about empirical formula:

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7 0

2 years ago