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2 years ago

Would baking two or more ingredients be a mixture?

Chemistry

2 answers:

kkurt [141]2 years ago

6 0

Answer:

Yes

Explanation:

Because mixture is made up of two or more types of atoms .

ipn [44]2 years ago

6 0

Answer:

yes it would

Explanation:

this is because when u bake the substances are chemically combined

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ycow [4]

Answer:

Heterogeneous

Explanation:

3 0

2 years ago

A chemist takes 50-gram sample of sulfur powder that has a melting point of 115.2 °C. What is the melting point of a 100-gram sa

Viktor [21]

Answer:

115.2 °C since melting point is an intensive property

Step-by-step explanation:

The melting point of a substance does not depend on how much you have.

For example, the melting point of water is 0 °C, whether it is an ice cube from the refrigerator or in the frozen pond outside.

The freezing point of a substance is an <em>intensive property</em>.

Thus, the melting point of 100 g of sulfur is 115.2 °C because melting point in an intensive property.

7 0

3 years ago

How many moles are in 288.6 grams of titanium? Round your answer to the nearest hundredth. Be sure to include units.

Shtirlitz [24]

Answer:

Raw:

Namber of mole =mass/molar mass

5 0

2 years ago

The diagram below represents a sodium atom bonding to a chlorine atom to form sodium chlorine.

Sergio [31]

Sodium Chloride is a compound.

8 0

3 years ago

A solution is made by mixing of water and of acetic acid . Calculate the mole fraction of water in this solution. Be sure your a

Molodets [167]

Answer:

The answer is "0.35".

Explanation:

please find the complete question in the attached file.

Mass of $CH_3C0_2 H$ $= 77 \ g \\\\$

Molar mass of $CH_3C0_2 H$ $= 60.05 \ \frac{g}{mol} \\\\$

No of moles in $n_{CH_3CO_2H}$ $= 77 \ g \times \frac{1 \ mol \ CH_3C0_2H}{60.05 \ g}$

$= 1.28 \ mol \ CH_3CO_2H$

Mass of water $(H_2O)$ $= 42 \ g$

The molar mass of water $(H_2O)$ $= 18.02 \ \frac{g}{mol}$

moles of water $n_{H_2O}$ :

$= 42 \ g \times \frac{1 mol H_2O}{18.02 \ g} \\\\= 2.33 \ mol \ H_2 O$

Molfraction of acetic acid:

$X CH_2CO_2H = \frac{n_{CH_3CO_2H}}{n_CH_3CO_2H +n_{H_2}}\\\\$

$=\frac{1.28 \ mol}{1.28 \ mo1 + 2.33 mol}\\\\ = 0.354\\\\= 0.35$

7 0

3 years ago