Answer: 117.6N
Explanation:
By the second Newton's law, we know that:
F = m*a
F = force
m = mass
a = acceleration
We know that in the surface of the Earth, the gravitational acceleration is g = 9.8m/s^2.
Then we just can input that acceleration in the above equation, and also replace m by 12kg, and find that the force due the gravity is:
F = 12kg*9.8m/s^2 = 117.6N
Answer:
The deceleration of the dragster upon releasing the parachute such that the wheels at B are on the verge of leaving the ground is 16.33 m/s²
Explanation:
The additional information to the question is embedded in the diagram attached below:
The height between the dragster and ground is considered to be 0.35 m since is not given ; thus in addition win 0.75 m between the dragster and the parachute; we have: (0.75 + 0.35) m = 1.1 m
Balancing the equilibrium about point A;
F(1.1) - mg (1.25) = 
- 1200(9.8)(1.25) = 1200a(0.35)
- 14700 = 420 a ------- equation (1)
--------- equation (2)
Replacing equation 2 into equation 1 ; we have :
1320 a - 14700 = 420 a
1320 a - 420 a =14700
900 a = 14700
a = 14700/900
a = 16.33 m/s²
The deceleration of the dragster upon releasing the parachute such that the wheels at B are on the verge of leaving the ground is 16.33 m/s²
Answer:
The forces are exerted on different objects so they are not balanced forces.
Explanation:
Answer:
All of these answers are dependent upon the specific scenario, but here are some general answers.
1. An object with a greater height will have more potential energy.
2. Potential energy can be changed into kinetic energy as an object falls. It loses height (potential energy) and gains speed (kinetic energy).
3. Depends on what scenario your class had.
Answer:
The smallest integer is n = 4
Explanation:
Using the equation V= Sqrt(F/Linear density)
V= Sqrt(341/0.0120)
V= Sqrt(28416.7)
V= 168.57m/s
Path distance =[ (n +1)/2]lambda
But V= f(Lambda)
n lambda/2 =L
n = f2L/V
n = (20 × 2 × 16.86) / 168.57
n = 4.0007
The smallest integer is n= 4
